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|dw:1364048045697:dw|

\[h(t)=t-4\sqrt{t+1}\]?

i guess you need the first two derivatives
what did you get for the first one?

@satellite73 give me a second im gonna do it right now

ok

the first derivate is

|dw:1364048369021:dw|

yes it is
i would write it as
\[1-\frac{2}{\sqrt{t+1}}\] but that is correct.

okay

a bit confused here?

is that okay?

so you put zero in place of t right

no, you set the derivative equal to zero and solve for \(t\)

i.e. solve
\[1-\frac{2}{\sqrt{t+1}}+0\]

damn typo!!

\[1-\frac{2}{\sqrt{t+1}}=0\]

t=+sqrt(2)-1,-sqrt(2)-1

thats better

okay ill give it a try

so t=3 ?

yes

yay! lol

now you have two critical points, \(t=0\) and \(t=3\)

oh sorry in a hurry id did a mistake t=3 and -6

second derivative is ... ?

okay im working on it @satellite73

second derivative is (t+1)^(-3/2)

would it be

|dw:1364049467577:dw|

\[\frac{1}{\sqrt{t+1}^3}\]

close enough lol

yep thats what i was referring to as derivative that is of satellite73

so im evaluating right ?

yes

1/16

no i get \(\frac{1}{8}\) but in any case it is positive which is all you really care about

its 1/8

i forgot to
simplify

would that be all

yep

oh okay lol

thanks guys (:

oh okay @satellite73