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anonymous
 3 years ago
determine the limits and evaluate..
∫∫x2y2dA
where f is a figure bounded by F lines y = 1, y = 2 and x = 0, x = y
anonymous
 3 years ago
determine the limits and evaluate.. ∫∫x2y2dA where f is a figure bounded by F lines y = 1, y = 2 and x = 0, x = y

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364052128248:dw that gives you the limits

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is easier to travel on yaxis because there is no sudden breaks

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so \[0\le x\le y \qquad\text{&}\qquad1\le y\le2\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if you are on the xaxis, you have to consider two pieces A) \(1\le y\le2 \qquad\text{&}\qquad0\le x\le1\) B) \(x\le y\le2 \qquad\text{&}\qquad1\le x\le2\) and sum them

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0in x=y, the value of y will become a and 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0all points on the "x=y" line will have the same abscissa and ordinate

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yup, in the problem, all you need are the limits

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0will i add these A) 1≤y≤2&0≤x≤1 B) x≤y≤2&1≤x≤2 ??

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0use the first method its easier.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes those are your two regions for the second method

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0x=0 to 1 and y= 1 to 2 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no x=0 to y and y=1 to 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364053324530:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i will integrate x^2y^2 using the limits x=0 to y and y=1 to 2 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0methid "1" is the horizontal element method "2" is the vertical

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ah ok.. in \[\int\limits_{1}^{2}\int\limits_{0}^{y} x^2y^2 dxdy\], got 127/36.. is it right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \int_{y=1}^2y^2\left[x^3\over3\right]_0^ydy={1\over3\times6}\left[y^6\right]_1^2 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0127/36 = 3.53 7/2 = 3.5 my answer is 127/36 :)) its almost the same :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364054668113:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@electrokid ? look at my answer?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0great job :D I'd personally not like to have many terms while integrating ... it gives migraine without it!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you!so is my answer also correct?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you! tnx for ur time :)
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