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jedai17
Group Title
determine the limits and evaluate..
∫∫x2y2dA
where f is a figure bounded by F lines y = 1, y = 2 and x = 0, x = y
 one year ago
 one year ago
jedai17 Group Title
determine the limits and evaluate.. ∫∫x2y2dA where f is a figure bounded by F lines y = 1, y = 2 and x = 0, x = y
 one year ago
 one year ago

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electrokid Group TitleBest ResponseYou've already chosen the best response.1
dw:1364052128248:dw that gives you the limits
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
it is easier to travel on yaxis because there is no sudden breaks
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
so \[0\le x\le y \qquad\text{&}\qquad1\le y\le2\]
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
if you are on the xaxis, you have to consider two pieces A) \(1\le y\le2 \qquad\text{&}\qquad0\le x\le1\) B) \(x\le y\le2 \qquad\text{&}\qquad1\le x\le2\) and sum them
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
follow?
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
in x=y, the value of y will become a and 2?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
all points on the "x=y" line will have the same abscissa and ordinate
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
yup, in the problem, all you need are the limits
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
will i add these A) 1≤y≤2&0≤x≤1 B) x≤y≤2&1≤x≤2 ??
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
use the first method its easier.
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
yes those are your two regions for the second method
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
x=0 to 1 and y= 1 to 2 ?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
no x=0 to y and y=1 to 2
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
dw:1364053324530:dw
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
i will integrate x^2y^2 using the limits x=0 to y and y=1 to 2 ?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
methid "1" is the horizontal element method "2" is the vertical
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
yep. you got it
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
ah ok.. in \[\int\limits_{1}^{2}\int\limits_{0}^{y} x^2y^2 dxdy\], got 127/36.. is it right?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
\[ \int_{y=1}^2y^2\left[x^3\over3\right]_0^ydy={1\over3\times6}\left[y^6\right]_1^2 \]
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
.. wait..
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
false alarm
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
\[dA=dxdy\]
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
kapeesh?
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
127/36 = 3.53 7/2 = 3.5 my answer is 127/36 :)) its almost the same :)
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
dw:1364054668113:dw
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
@electrokid ? look at my answer?
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
great job :D I'd personally not like to have many terms while integrating ... it gives migraine without it!
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
thank you!so is my answer also correct?
 one year ago

jedai17 Group TitleBest ResponseYou've already chosen the best response.0
thank you! tnx for ur time :)
 one year ago

electrokid Group TitleBest ResponseYou've already chosen the best response.1
yer welcome :)
 one year ago
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