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prove that the directrix of an ellipse is \[x=\frac{a^2}{c}\]

Geometry
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this ellipse is the general ellipse with \[\frac{ x^2 }{ a^2}+\frac{ y^2 }{ b^2 }=1,a>b\]
i have the proof but i dont understand the ratio set up here can i post the link
http://mathworld.wolfram.com/Ellipse.html

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Other answers:

\[r=\frac{ a-c }{ d-a }=\frac{ a }{ d }\]
\[a^2=b^2+c^2 i dont get this ratio .why it holds
??|dw:1364055606757:dw||dw:1364055629069:dw|
i haven't done conics for quite while, but this shouldn't be difficult.|dw:1364055735803:dw|
i mean http://mathworld.wolfram.com/images/equations/Ellipse/NumberedEquation12.gif
what's r there?
its defined in the 1st link
can't find it ... equation no?
24
what is this 'c' again?
this 'c' looks like foci.
this is pretty ovbioius ... this ratio must be constant

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