## bridgetx516x one year ago Simplify the expression as much as possible: cscx / tanx+cotx

$\frac{ cosec(x) }{ \tan(x)+\cot(x) }= \frac{ \frac{ 1 }{ \sin(x) } }{ \frac{ \sin(x) }{ \cos(x) }+\frac{ \cos(x) }{ \sin(x) } }$ So if we move the sin(x) to the bottom like so $= \frac{ 1 }{ \sin(x)\frac{ \sin(x) }{ \cos(x) }+ \sin(x)\frac{ \cos(x) }{ \sin(x) } }$ Expand out the bottom further to get $= \frac{ 1 }{ \frac{ \sin^2(x) }{ \cos(x) }+\cos(x) }$ Now let cos(x)=cos^2(x)/cos(x) and take out a factor of 1/cos(x) on the bottom.$=\frac{ 1 }{ \frac{ \sin^2(x)+\cos^2(x) }{ \cos(x) } }$As we know, sin^2(x) + cos^2(x) = 1, so we are left with 1/(1/cos(x)) which is just $\frac{ cosec(x) }{ \tan(x)+\cot(x) }= \cos(x)$Hope this helped:)

2. NoelGreco

Paddy, you should have gotten a medal or at least a thank you for all that work!

3. NoelGreco

There, I gave you a medal.

4. bridgetx516x

THANK YOU SO MUCH!