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electrokidBest ResponseYou've already chosen the best response.0
@modphysnoob haha thats no help
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
*Use the left and right endpoints and the given number of rectangles to find two approximations of the area of the region between the graph of the function and the xaxis over the given interval. g(x) = 2x^2x1, [2,5], 6 rectangles
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
this is approximation
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
I will draw a picture and explain this
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
dw:1364087469983:dw this is left hand approximation
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
dw:1364087569386:dw this is right hand approximation
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
see the difference?
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
One is above the curve, and one is below it, to put it simply. :)
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
right, but to be more precise in left hand approximation, the left side touch the curves, in right hand approx, the right side does
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
You mean that all of the left endpoints of each rectangle touch the curve for the right approximation and the same for the left? Just making sure that I follow.
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
Err, left approximation, not right in that first sentence.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
yes, right, so as you said, in left hand over approximate, right hand under approximate
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
All right. I know that you have divide the interval into subintervals. Since it's 6 rectangles, that means 6 subintervals, right?
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
so from 2 to 5 5 2  6 3/6 1/2
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
so each rectangle is 1/2 wide
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
Yeah, I was getting there! So, I understand that part. :)
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
dw:1364088406811:dw
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
So, for left hand approximation, I would use the left end points for each subinterval. So, the length of each rectangle would be g(x) evaluated at each left endpoint of that subinterval?
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
Okay. This is starting to make a little bit of sense, :) One big thing that confuses me is the Sigma notation that is adding in with this. :/
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
sigma just mean sum dw:1364090915002:dw
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
Yes, I know that much. It's just figuring out the pattern is where I have trouble.
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
I mean, I know that's going to be all the areas of rectangles added together.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
yep, that's all there is to it
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
I'll see if I can find some videos to help, too. :) Easier to grasp things when you see examples being worked out. But, at least, I understand a bit more! I can do this!
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
I assume you are in calculus 2
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
if you want I can do example for you
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
@modphysnoob  I know this a late reply, but by all means go for it, if you don't mind. :)
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
so let's do a parabola f(x)= x^2 dw:1364157776078:dw
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
dw:1364157838998:dw
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
so we wanna approximate the area under the curve using 2 rectangle so first rectangle would be from 0 to 1 1 to 2
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
0 1 2 in left approximation we will take 2 rectangles with height at 0 and 1 and multiply by width =1 f(0)*1+f(1)*1 in right approoximation , we take height at 1 and 2 f(1)*1+f(2)*1
 one year ago

MoonlitFateBest ResponseYou've already chosen the best response.0
Okay, I follow you so far. :) Sorry for the delay in answering; internet problems.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
well, there you have it , left and right approximation
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.2
you will learn trapizoid approximation which is average between left and right hand
 one year ago
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