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waheguru
 3 years ago
I am confused on how to find points on a circle. I am given that the equation is x^2+y^2=50
From here how do I find two points?
waheguru
 3 years ago
I am confused on how to find points on a circle. I am given that the equation is x^2+y^2=50 From here how do I find two points?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The line 3y+x=10 intersects the circle x^2+y^2=50 in two distinct points. Suppose you drew a radius to each of the two points of intersection. Find the angle, in standard position, created by each radius. .. Finding points of intersection 3y+x=10 x=103y x^2+y^2=50 (103y)^2+y^2=50 10060y+9y^2+y^2=50 10060y+10y^2=50 divide by 10 106y+y^2=5 y^26y+5=0 (y5)(y1)=0 y=5 x=103y=1015=5 y=1 x=103y=103=7 .. Points of intersection: (5,5) and (7,1) .. y=(50x^2)^.5 y=x/3+10/3 if you draw a line joining the center with the points of intersection, you will get two reference angles. The tangent of the reference angle on the right is 1/7. Taking the inverse tan of 1/7=8.13º. At the other point, the inverse tan=5/5=1=45º. The angle in standard position is 1808.1345=126.87º I'm pretty sure that trigonometry is needed for this problem, but I'm not totally sure! The line 3y+x=10 intersects the circle x^2+y^2=50 in two distinct points. Suppose you drew a radius to each of the two points of intersection. Find the angle, in standard position, created by each radius.

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0This is a very complicated way. We learned a very simple way but I canno't remember

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x ^{2}+y ^{2}=50\] so bring the y in one side \[y=\pm \sqrt{50x ^{2}}\] now whatever number instead of x and get it's y
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