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waheguru

  • one year ago

I need to prove that A(-12, -5) B(12, 5) and C(-12, 5) Is a right triangle. I know two adjacent angles need to be perpendicular but the slopes are -10/0 and 0/-24 which are not negative reciprocals?

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  1. modphysnoob
    • one year ago
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    |dw:1364140978728:dw| in right triangle , the circle point will have cordinates that is same as x of one and y of another

  2. modphysnoob
    • one year ago
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    |dw:1364141029806:dw|

  3. waheguru
    • one year ago
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    Yes

  4. waheguru
    • one year ago
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    Can you explain with the co-ordinates I have placed because the slopes are not negative reciporicals?

  5. modphysnoob
    • one year ago
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    A(-12, -5) B(12, 5) and C(-12, 5) C(-12,5) matches A's x coordinate matches B's y coordinate

  6. waheguru
    • one year ago
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    Ok, but Im supposed to prove that it is a right triangle by the slopes?

  7. modphysnoob
    • one year ago
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    |dw:1364141234813:dw|

  8. Ajk
    • one year ago
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    you have 3 points, so you can find the slopes of the lines connecting all three. you can also use the points, and the slopes you have found, to find the equations of the lines.

  9. modphysnoob
    • one year ago
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    line A to C have infinite slope

  10. modphysnoob
    • one year ago
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    C to B has 0 slope

  11. modphysnoob
    • one year ago
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    which are reciprocal

  12. waheguru
    • one year ago
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    SO my slopes are acuually negaitve reciporicals? 10/0 and 0/-24

  13. modphysnoob
    • one year ago
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    yep

  14. Ajk
    • one year ago
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    zero slope is horizontal, infinite slope is vertical. if they intersect, then by definition they would be at right angles, yeah?

  15. waheguru
    • one year ago
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    Thankyou

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