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waheguru

  • 3 years ago

I need to prove that A(-12, -5) B(12, 5) and C(-12, 5) Is a right triangle. I know two adjacent angles need to be perpendicular but the slopes are -10/0 and 0/-24 which are not negative reciprocals?

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  1. modphysnoob
    • 3 years ago
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    |dw:1364140978728:dw| in right triangle , the circle point will have cordinates that is same as x of one and y of another

  2. modphysnoob
    • 3 years ago
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    |dw:1364141029806:dw|

  3. waheguru
    • 3 years ago
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    Yes

  4. waheguru
    • 3 years ago
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    Can you explain with the co-ordinates I have placed because the slopes are not negative reciporicals?

  5. modphysnoob
    • 3 years ago
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    A(-12, -5) B(12, 5) and C(-12, 5) C(-12,5) matches A's x coordinate matches B's y coordinate

  6. waheguru
    • 3 years ago
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    Ok, but Im supposed to prove that it is a right triangle by the slopes?

  7. modphysnoob
    • 3 years ago
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    |dw:1364141234813:dw|

  8. Ajk
    • 3 years ago
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    you have 3 points, so you can find the slopes of the lines connecting all three. you can also use the points, and the slopes you have found, to find the equations of the lines.

  9. modphysnoob
    • 3 years ago
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    line A to C have infinite slope

  10. modphysnoob
    • 3 years ago
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    C to B has 0 slope

  11. modphysnoob
    • 3 years ago
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    which are reciprocal

  12. waheguru
    • 3 years ago
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    SO my slopes are acuually negaitve reciporicals? 10/0 and 0/-24

  13. modphysnoob
    • 3 years ago
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    yep

  14. Ajk
    • 3 years ago
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    zero slope is horizontal, infinite slope is vertical. if they intersect, then by definition they would be at right angles, yeah?

  15. waheguru
    • 3 years ago
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    Thankyou

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