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waheguru

I need to prove that A(-12, -5) B(12, 5) and C(-12, 5) Is a right triangle. I know two adjacent angles need to be perpendicular but the slopes are -10/0 and 0/-24 which are not negative reciprocals?

  • one year ago
  • one year ago

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  1. modphysnoob
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    |dw:1364140978728:dw| in right triangle , the circle point will have cordinates that is same as x of one and y of another

    • one year ago
  2. modphysnoob
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    |dw:1364141029806:dw|

    • one year ago
  3. waheguru
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    Yes

    • one year ago
  4. waheguru
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    Can you explain with the co-ordinates I have placed because the slopes are not negative reciporicals?

    • one year ago
  5. modphysnoob
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    A(-12, -5) B(12, 5) and C(-12, 5) C(-12,5) matches A's x coordinate matches B's y coordinate

    • one year ago
  6. waheguru
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    Ok, but Im supposed to prove that it is a right triangle by the slopes?

    • one year ago
  7. modphysnoob
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    |dw:1364141234813:dw|

    • one year ago
  8. Ajk
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    you have 3 points, so you can find the slopes of the lines connecting all three. you can also use the points, and the slopes you have found, to find the equations of the lines.

    • one year ago
  9. modphysnoob
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    line A to C have infinite slope

    • one year ago
  10. modphysnoob
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    C to B has 0 slope

    • one year ago
  11. modphysnoob
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    which are reciprocal

    • one year ago
  12. waheguru
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    SO my slopes are acuually negaitve reciporicals? 10/0 and 0/-24

    • one year ago
  13. modphysnoob
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    yep

    • one year ago
  14. Ajk
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    zero slope is horizontal, infinite slope is vertical. if they intersect, then by definition they would be at right angles, yeah?

    • one year ago
  15. waheguru
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    Thankyou

    • one year ago
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