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bridgetx516x

  • 3 years ago

cscx/cosx - cosx/sinx. simplify as much as possible

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  1. electrokid
    • 3 years ago
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    \[\csc x=\frac{1}{\sin x}\\ \frac{\csc x}{\cos x}-\frac{\cos x}{\sin x}=\frac{1}{\cos x\sin x}-\frac{\cos x}{\sin x}\\ = \frac{1-\cos^2 x}{\cos x\sin x}\] you can go from there, right?

  2. electrokid
    • 3 years ago
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    the answer should be \(\tan x\)

  3. bridgetx516x
    • 3 years ago
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    yess thank you!!!

  4. electrokid
    • 3 years ago
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    :)

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