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missbdoll

  • 3 years ago

If sinA=5/6, where angle A is in Quadrant 1, find the exact value of sin (1/2A)

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  1. Notamathgenius
    • 3 years ago
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    1,172cm(2)

  2. NoelGreco
    • 3 years ago
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    I assume that's sin (.5A). There is a half-angle formula for sin.

  3. missbdoll
    • 3 years ago
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    so can you please help me solve the problem?

  4. ajprincess
    • 3 years ago
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    \[\cos^2A+\sin^2A=1\]\[\cos A=\sqrt{1-\sin^2A}\] From this \(\cos A\) can be found u can find \(\cos A\). Then use \[\cos A=1-2\sin^2(\frac{ 1 }{ 2 }A)\]\[\sin \frac{ 1 }{ 2 }A=\sqrt{\frac{ 1-\cos A }{ 2 }}\] from this u can find \[\sin \frac{ 1 }{2}A\] Does that help?

  5. missbdoll
    • 3 years ago
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    but do u have an answer?

  6. Notamathgenius
    • 3 years ago
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    Mine is at the very top

  7. missbdoll
    • 3 years ago
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    did u use the half-angle formula because i'm getting a radical?

  8. ajprincess
    • 3 years ago
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    what r u getting?

  9. missbdoll
    • 3 years ago
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    |dw:1364227944196:dw|

  10. ajprincess
    • 3 years ago
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    |dw:1364228079352:dw||dw:1364228136955:dw| |dw:1364228182827:dw|

  11. ajprincess
    • 3 years ago
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    getting it?

  12. missbdoll
    • 3 years ago
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    is that the complete answer?

  13. ajprincess
    • 3 years ago
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    yup

  14. missbdoll
    • 3 years ago
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    ok thank you so much

  15. ajprincess
    • 3 years ago
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    Welcome:) do u get it?

  16. missbdoll
    • 3 years ago
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    yes :)

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