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missbdoll Group Title

If sinA=5/6, where angle A is in Quadrant 1, find the exact value of sin (1/2A)

  • one year ago
  • one year ago

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  1. Notamathgenius Group Title
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    1,172cm(2)

    • one year ago
  2. NoelGreco Group Title
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    I assume that's sin (.5A). There is a half-angle formula for sin.

    • one year ago
  3. missbdoll Group Title
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    so can you please help me solve the problem?

    • one year ago
  4. ajprincess Group Title
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    \[\cos^2A+\sin^2A=1\]\[\cos A=\sqrt{1-\sin^2A}\] From this \(\cos A\) can be found u can find \(\cos A\). Then use \[\cos A=1-2\sin^2(\frac{ 1 }{ 2 }A)\]\[\sin \frac{ 1 }{ 2 }A=\sqrt{\frac{ 1-\cos A }{ 2 }}\] from this u can find \[\sin \frac{ 1 }{2}A\] Does that help?

    • one year ago
  5. missbdoll Group Title
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    but do u have an answer?

    • one year ago
  6. Notamathgenius Group Title
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    Mine is at the very top

    • one year ago
  7. missbdoll Group Title
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    did u use the half-angle formula because i'm getting a radical?

    • one year ago
  8. ajprincess Group Title
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    what r u getting?

    • one year ago
  9. missbdoll Group Title
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    |dw:1364227944196:dw|

    • one year ago
  10. ajprincess Group Title
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    |dw:1364228079352:dw||dw:1364228136955:dw| |dw:1364228182827:dw|

    • one year ago
  11. ajprincess Group Title
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    getting it?

    • one year ago
  12. missbdoll Group Title
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    is that the complete answer?

    • one year ago
  13. ajprincess Group Title
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    yup

    • one year ago
  14. missbdoll Group Title
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    ok thank you so much

    • one year ago
  15. ajprincess Group Title
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    Welcome:) do u get it?

    • one year ago
  16. missbdoll Group Title
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    yes :)

    • one year ago
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