missbdoll
If sinA=5/6, where angle A is in Quadrant 1, find the exact value of sin (1/2A)
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Notamathgenius
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1,172cm(2)
NoelGreco
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I assume that's sin (.5A). There is a half-angle formula for sin.
missbdoll
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so can you please help me solve the problem?
ajprincess
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\[\cos^2A+\sin^2A=1\]\[\cos A=\sqrt{1-\sin^2A}\]
From this \(\cos A\) can be found
u can find \(\cos A\).
Then use
\[\cos A=1-2\sin^2(\frac{ 1 }{ 2 }A)\]\[\sin \frac{ 1 }{ 2 }A=\sqrt{\frac{ 1-\cos A }{ 2 }}\]
from this u can find
\[\sin \frac{ 1 }{2}A\]
Does that help?
missbdoll
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but do u have an answer?
Notamathgenius
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Mine is at the very top
missbdoll
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did u use the half-angle formula because i'm getting a radical?
ajprincess
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what r u getting?
missbdoll
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|dw:1364227944196:dw|
ajprincess
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|dw:1364228079352:dw||dw:1364228136955:dw|
|dw:1364228182827:dw|
ajprincess
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getting it?
missbdoll
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is that the complete answer?
ajprincess
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yup
missbdoll
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ok thank you so much
ajprincess
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Welcome:) do u get it?
missbdoll
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yes :)