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ilikequadraticsokay
 2 years ago
Solve the system by elimination;
4a  2b + 3c = 10
5a + 2b  2c = 28
3a  2b + c = 22
ilikequadraticsokay
 2 years ago
Solve the system by elimination; 4a  2b + 3c = 10 5a + 2b  2c = 28 3a  2b + c = 22

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timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0pic one variable of one equation and solve for it. LIke pick c of bottom most equation and solve for it then plug it into middle equation

ilikequadraticsokay
 2 years ago
Best ResponseYou've already chosen the best response.0how do you eliminate the a and b though?

ilikequadraticsokay
 2 years ago
Best ResponseYou've already chosen the best response.0i end up with 4a  2b + 3c = 10 5a + 2b  2c = 28 3a  2b + c = 22 4a  2b + 3c = 10 5a + 2b  2c = 28 c = 22 + 3a +2b

kelliegirl33
 2 years ago
Best ResponseYou've already chosen the best response.2take the first two equations and add them...this will cancel out the b's

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0wait i was doing substitution sorry @ilikequadraticsokay

timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0the link i gave has a great example

kelliegirl33
 2 years ago
Best ResponseYou've already chosen the best response.24a  2b + 3c =  10 5a + 2b  2c =  28  9a + c =  38 now take the next two equations and eliminate b. 5a + 2b  2c =  28 3a  2b + c = 22  2a  c =  6 now take the 2 equations you came up with...the ones you cancelled out the b's in. 9a + c =  38 2a  c =  6  11a =  44 a =  4 now sub 4 in for a in either of the above equations 9a + c =  38 9(4) + c =  38  36 + c =  38 c =  38 + 36 c =  2 now sub known values into any of the original equations 4a  2b + 3c = 10 4(4)  2b + 3(2) =  10 16  2b  6 =  10 2b =  10 + 22 2b = 12 b = 6 lets check... 5a + 2b  2c =  28 5(4) + 2(6)  2(2) =  28 20  12 + 4 =  28  32 + 4 =  28  28 =  28 (correct) a = 4, b = 6, c = 2 Is there anything I have just done that you don't understand ? I will be happy to explain it to you.

ilikequadraticsokay
 2 years ago
Best ResponseYou've already chosen the best response.0You explained this perfectly, thank you!
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