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 one year ago
laplace transform of \[f(t)=u_1(t)+2u_3(t)6u_4(t)\]and the answer is \[F(s)=s^{2}[(1s)e^{2s}(1+s)e^{3s}]\]but I dont know how to get this
 one year ago
laplace transform of \[f(t)=u_1(t)+2u_3(t)6u_4(t)\]and the answer is \[F(s)=s^{2}[(1s)e^{2s}(1+s)e^{3s}]\]but I dont know how to get this

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johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0All I know is that the laplace of \(u_c(t)\)=\[\frac{e^{cs}}{s}\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0Have to get the smart guys to help you with this.

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1well, you got the table right?

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0so with the identity I have \[F(s)=\frac{e^{s}}{s}+2\frac{e^{3s}}{s}6\frac{e^{4s}}{s}\]and how do I make it look like the answer I have above?

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0and yes i do have the table

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1alright, let's try something different

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0i have another identity regarding step functions, it's this \[u_c(t)f(tc)=>e^{cs}F(s)\]

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1do you know how they look like though?

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364173680082:dw

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0guys i apologize sincerely....... it looks like I have read the wrong answer to the problem......

johnny0929
 one year ago
Best ResponseYou've already chosen the best response.0sorry and thanks for your help!!

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1i was gonna say...

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1\[f(t)=u_1(t)+2u_3(t)6u_4(t)\] \[\mathcal L\big\{f(t)\big\}=\mathcal L\big\{u_1(t)\big\}+2\mathcal L\big\{u_3(t)\big\}6\mathcal L\big\{u_4(t)\big\}\\\qquad\qquad=\frac {e^{s}}s+2\frac {e^{3s}}s6\frac {e^{4s}}s\\\qquad F(s)=\frac1s\big(e^{s}+2e^{3s}6e^{4s}\big)\]

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.0table looks like this dw:1364174488647:dw

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364174630421:dw
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