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laplace transform of \[f(t)=u_1(t)+2u_3(t)6u_4(t)\]and the answer is \[F(s)=s^{2}[(1s)e^{2s}(1+s)e^{3s}]\]but I dont know how to get this
 one year ago
 one year ago
laplace transform of \[f(t)=u_1(t)+2u_3(t)6u_4(t)\]and the answer is \[F(s)=s^{2}[(1s)e^{2s}(1+s)e^{3s}]\]but I dont know how to get this
 one year ago
 one year ago

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johnny0929Best ResponseYou've already chosen the best response.0
All I know is that the laplace of \(u_c(t)\)=\[\frac{e^{cs}}{s}\]
 one year ago

MertsjBest ResponseYou've already chosen the best response.0
Have to get the smart guys to help you with this.
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.1
well, you got the table right?
 one year ago

johnny0929Best ResponseYou've already chosen the best response.0
so with the identity I have \[F(s)=\frac{e^{s}}{s}+2\frac{e^{3s}}{s}6\frac{e^{4s}}{s}\]and how do I make it look like the answer I have above?
 one year ago

johnny0929Best ResponseYou've already chosen the best response.0
and yes i do have the table
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.1
alright, let's try something different
 one year ago

johnny0929Best ResponseYou've already chosen the best response.0
i have another identity regarding step functions, it's this \[u_c(t)f(tc)=>e^{cs}F(s)\]
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.1
do you know how they look like though?
 one year ago

modphysnoobBest ResponseYou've already chosen the best response.1
dw:1364173680082:dw
 one year ago

johnny0929Best ResponseYou've already chosen the best response.0
guys i apologize sincerely....... it looks like I have read the wrong answer to the problem......
 one year ago

johnny0929Best ResponseYou've already chosen the best response.0
sorry and thanks for your help!!
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i was gonna say...
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[f(t)=u_1(t)+2u_3(t)6u_4(t)\] \[\mathcal L\big\{f(t)\big\}=\mathcal L\big\{u_1(t)\big\}+2\mathcal L\big\{u_3(t)\big\}6\mathcal L\big\{u_4(t)\big\}\\\qquad\qquad=\frac {e^{s}}s+2\frac {e^{3s}}s6\frac {e^{4s}}s\\\qquad F(s)=\frac1s\big(e^{s}+2e^{3s}6e^{4s}\big)\]
 one year ago

nincompoopBest ResponseYou've already chosen the best response.0
table looks like this dw:1364174488647:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
dw:1364174630421:dw
 one year ago
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