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anonymous
 3 years ago
Please Help!!
The rate of a chemical reaction normally _____. (1 point)
decreases as temperature increases
is slowed down by a catalyst
increases as reactant concentration increases
decreases as reactant concentration increases
anonymous
 3 years ago
Please Help!! The rate of a chemical reaction normally _____. (1 point) decreases as temperature increases is slowed down by a catalyst increases as reactant concentration increases decreases as reactant concentration increases

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0increases as reactant concentration increases. Your in NDCDE!! LoL

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0please help me in this: Use the law of conservation of mass to explain why a chemical equation must be balanced.

Frostbite
 3 years ago
Best ResponseYou've already chosen the best response.1Foxhunter you kinda answer your own question... if mass most be conserved you can't have that some elements are just gone...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you please explain it in detail. plzzzzzzzzzzzzzz i am pellet in chemestry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i am stupid in chemestry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@foxhunter98 http://answers.yahoo.com/question/index?qid=20100412164929AAuPxRy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@foxhunter98 Then how did you answer my question??

Frostbite
 3 years ago
Best ResponseYou've already chosen the best response.1I sure can... Lets consider we have a reaction called 2 A +9 B > 5 C + 2 D. To say this in words: 2 moles of A react with 9 moles of B to create 5 moles of C and 2 moles of D. So for the calculations to work out we need to say (for a reaction assuming that all the reactants are converted): \[\sum_{}^{}m(reactants)=\sum_{}^{}m(products+waist)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Frostbite can u answer my question as well?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks @foxhunter98 your answer was correct :))
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