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 one year ago
Please Help!!
The rate of a chemical reaction normally _____. (1 point)
decreases as temperature increases
is slowed down by a catalyst
increases as reactant concentration increases
decreases as reactant concentration increases
 one year ago
Please Help!! The rate of a chemical reaction normally _____. (1 point) decreases as temperature increases is slowed down by a catalyst increases as reactant concentration increases decreases as reactant concentration increases

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foxhunter98
 one year ago
Best ResponseYou've already chosen the best response.1increases as reactant concentration increases. Your in NDCDE!! LoL

foxhunter98
 one year ago
Best ResponseYou've already chosen the best response.1please help me in this: Use the law of conservation of mass to explain why a chemical equation must be balanced.

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1Foxhunter you kinda answer your own question... if mass most be conserved you can't have that some elements are just gone...

foxhunter98
 one year ago
Best ResponseYou've already chosen the best response.1can you please explain it in detail. plzzzzzzzzzzzzzz i am pellet in chemestry

foxhunter98
 one year ago
Best ResponseYou've already chosen the best response.1i am stupid in chemestry

zhane2015
 one year ago
Best ResponseYou've already chosen the best response.0@foxhunter98 http://answers.yahoo.com/question/index?qid=20100412164929AAuPxRy

zhane2015
 one year ago
Best ResponseYou've already chosen the best response.0@foxhunter98 Then how did you answer my question??

Frostbite
 one year ago
Best ResponseYou've already chosen the best response.1I sure can... Lets consider we have a reaction called 2 A +9 B > 5 C + 2 D. To say this in words: 2 moles of A react with 9 moles of B to create 5 moles of C and 2 moles of D. So for the calculations to work out we need to say (for a reaction assuming that all the reactants are converted): \[\sum_{}^{}m(reactants)=\sum_{}^{}m(products+waist)\]

zhane2015
 one year ago
Best ResponseYou've already chosen the best response.0@Frostbite can u answer my question as well?

zhane2015
 one year ago
Best ResponseYou've already chosen the best response.0Thanks @foxhunter98 your answer was correct :))
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