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Firejay5
 one year ago
Simplify Each Expression. Show work and explain it.
32. m over m^2  4 + 2 over 3m + 6
Firejay5
 one year ago
Simplify Each Expression. Show work and explain it. 32. m over m^2  4 + 2 over 3m + 6

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Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0Well on #32, I am having trouble multiplying the denominators to make them the same

wio
 one year ago
Best ResponseYou've already chosen the best response.0"m over m^2  4 + 2 over 3m + 6" \[ \frac{m}{m^24}+\frac{2}{3m+6} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.0Just use this: \[ \frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.0I think the + is separating two fractions.

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0can you do it with me and then I'll do 33.) my self

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0can we get back to the problem

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0the example he gave isn't going nowhere for me

wio
 one year ago
Best ResponseYou've already chosen the best response.0let \(b=m^24\) and \(d=3m+6\)

wio
 one year ago
Best ResponseYou've already chosen the best response.0\[ \frac{m}{m^24}+\frac{2}{3m+6}=\frac{(m)(3m+6)+(2)(m^24)}{(m^24)(3m+6)} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.0@Firejay5 Do you see the pattern?

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0Yes? Kind of how did you get that

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0I need full out steps, like getting the denominators equal, etc.

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0@Mertsj could you help with that

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1hmn . \[\frac{m}{m^24}+\frac{2}{3m+6}\] Well I think that it would be Ok to factorize both denominators

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Yes. mathslover will be able to show you.

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{m^24}\) is in the form of \(a^2b^2\) \(a^2b^2 = (a+b)(ab)\) Use the above stated identity to factorize \(m^24 \) .

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Can you factor \(m^24\) @Firejay5 ?

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Can you tell me what would be the factorized form for \(x^24\) ?

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Great! So \(x^24 = \color{blue}{(x+2)(x2)}\) Now. we have the complete question as : \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{3m+6}\)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Now take 3 common from 3m + 6. What you get?

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0I did the other factorization as well

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Great! \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{\color{orange}{3(m+2)}}\). Is what we have now.

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1LCM of \(\cfrac{1}{a+b} + \cfrac{1}{2(ab)} \) (denominators) is (a+b)(ab)2

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Similarly do that there. we have \((x+2)(x2) \quad\textbf{and}\quad 3(m+2)\) as the denominators

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0it would be 3(m  2) (m + 2)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Yeah . and sorry there for using x on the place of m

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1So I have : 3(m2)(m+2) as LCM can you solve the fraction :

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0so what would it be entered in equation editor

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1I didn't get you,, please explain!

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0type the problem in fraction form of what we have left

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1hmn well it would be hard to say that I have : \(\cfrac{\textbf{yet to come}}{3(m+2)(m2)}\)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1we have to solve numerator now

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0wouldn't the numerator m + 2

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1No! See : \(\cfrac{1}{(a+b)} + \cfrac{2}{(ab)} = \cfrac{1(ab) + 2(a+b)}{(ab)(a+b)}\)

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0how does it work, you should + across

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364264397027:dw

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1See i have LCM as 3(m+2)(m2) I divided LCM by the first fraction's denominator that is (m+2)(m2) to get 3 . Now I multiplied this 3 by the first fractions' numerator that is m

wio
 one year ago
Best ResponseYou've already chosen the best response.0Wow, finding the LCM is makes it complicated.

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Similarly for the second one.. I have LCM as 3(m+2)(m2) I divided this LCM by the denominator of the second fraction 3(m+2) \(\cfrac{\cancel{3(m+2)} (m2)}{\cancel{3(m+2)} }\)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Does that mean you don't get it @Firejay5 ?

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0are the denominators the same

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364264678904:dw

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0whatever you multiply to the bottom, you must do to the top

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0work the problem a whole different way

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364264834069:dw

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1The LCM would be : 2(a+c)(ac)

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0let's work the problem a different way and not factorize, and get the denominators the same

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Yes , that would be easy for u.

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Well which denominator you want to be changed

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0You're way is not what we were taught in class and is confusing me. 3m + 6

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Sorry, ok let us change 3(m+2)

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1Would you try that for once?

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1to change the denominator ?

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1ok! I have first denominator as (m+2)(m2) and other one as 3(m+2) I want to make 3(m+2) = (m+2)(m2) For that I think I should multiply 3(m+2) by \(\cfrac{(m2)}{3}\)

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0where did you get m  2 over 3

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0don't jump ahead, it feels like you are just picking random numbers and variable from the problem

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Are you all clear now, Firejay?

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0kind of would you explain it the same way

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Do you want to talk about the original problem or what?

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0It feels like I am being taught a whole different then I learned it in class

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1I just want to make sure we are talking about the right problem. Is this it:

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1When you add fractions you need to have the denominators the same. So we have to build the common denominator.

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0@mathslover you did good though! :D

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1For the first denominator we need the factors m2 and m+2. For the second denominator we need the factors 3 and m+2. But we already have m+2. So the 3 factors we need are 3(m2)(m+2)

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1Are you with me so far?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1And finally: dw:1364266416514:dw

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0does it matter which order the m  2 or m + 2 goes

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0I put 5m  4 over 3(m + 2)(m  2)

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0How would you type 33.) y over y + 3 () 6y over y^2  9 in Wolframalpha

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{y}{y+3}\frac{6y}{y^29}\]

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1For wolf: y/(y+3)(6y)/(y^29)

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0which of the alternative forms are the answer

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.1That's the abbreviated version.

Firejay5
 one year ago
Best ResponseYou've already chosen the best response.0is it the first, second, or third one
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