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Simplify Each Expression. Show work and explain it.
32. m over m^2  4 + 2 over 3m + 6
 one year ago
 one year ago
Simplify Each Expression. Show work and explain it. 32. m over m^2  4 + 2 over 3m + 6
 one year ago
 one year ago

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Firejay5Best ResponseYou've already chosen the best response.0
Well on #32, I am having trouble multiplying the denominators to make them the same
 one year ago

wioBest ResponseYou've already chosen the best response.0
"m over m^2  4 + 2 over 3m + 6" \[ \frac{m}{m^24}+\frac{2}{3m+6} \]
 one year ago

wioBest ResponseYou've already chosen the best response.0
Just use this: \[ \frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd} \]
 one year ago

wioBest ResponseYou've already chosen the best response.0
I think the + is separating two fractions.
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
can you do it with me and then I'll do 33.) my self
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
can we get back to the problem
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
the example he gave isn't going nowhere for me
 one year ago

wioBest ResponseYou've already chosen the best response.0
let \(b=m^24\) and \(d=3m+6\)
 one year ago

wioBest ResponseYou've already chosen the best response.0
\[ \frac{m}{m^24}+\frac{2}{3m+6}=\frac{(m)(3m+6)+(2)(m^24)}{(m^24)(3m+6)} \]
 one year ago

wioBest ResponseYou've already chosen the best response.0
@Firejay5 Do you see the pattern?
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
Yes? Kind of how did you get that
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
I need full out steps, like getting the denominators equal, etc.
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
@Mertsj could you help with that
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
hmn . \[\frac{m}{m^24}+\frac{2}{3m+6}\] Well I think that it would be Ok to factorize both denominators
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
Yes. mathslover will be able to show you.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
\(\color{blue}{m^24}\) is in the form of \(a^2b^2\) \(a^2b^2 = (a+b)(ab)\) Use the above stated identity to factorize \(m^24 \) .
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Can you factor \(m^24\) @Firejay5 ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Can you tell me what would be the factorized form for \(x^24\) ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Great! So \(x^24 = \color{blue}{(x+2)(x2)}\) Now. we have the complete question as : \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{3m+6}\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Now take 3 common from 3m + 6. What you get?
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
I did the other factorization as well
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Great! \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{\color{orange}{3(m+2)}}\). Is what we have now.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
LCM of \(\cfrac{1}{a+b} + \cfrac{1}{2(ab)} \) (denominators) is (a+b)(ab)2
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Similarly do that there. we have \((x+2)(x2) \quad\textbf{and}\quad 3(m+2)\) as the denominators
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
it would be 3(m  2) (m + 2)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Yeah . and sorry there for using x on the place of m
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
So I have : 3(m2)(m+2) as LCM can you solve the fraction :
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
so what would it be entered in equation editor
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
I didn't get you,, please explain!
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
type the problem in fraction form of what we have left
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
hmn well it would be hard to say that I have : \(\cfrac{\textbf{yet to come}}{3(m+2)(m2)}\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
we have to solve numerator now
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
wouldn't the numerator m + 2
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
No! See : \(\cfrac{1}{(a+b)} + \cfrac{2}{(ab)} = \cfrac{1(ab) + 2(a+b)}{(ab)(a+b)}\)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
how does it work, you should + across
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
dw:1364264397027:dw
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
See i have LCM as 3(m+2)(m2) I divided LCM by the first fraction's denominator that is (m+2)(m2) to get 3 . Now I multiplied this 3 by the first fractions' numerator that is m
 one year ago

wioBest ResponseYou've already chosen the best response.0
Wow, finding the LCM is makes it complicated.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Similarly for the second one.. I have LCM as 3(m+2)(m2) I divided this LCM by the denominator of the second fraction 3(m+2) \(\cfrac{\cancel{3(m+2)} (m2)}{\cancel{3(m+2)} }\)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Does that mean you don't get it @Firejay5 ?
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
are the denominators the same
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
dw:1364264678904:dw
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
whatever you multiply to the bottom, you must do to the top
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
work the problem a whole different way
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
dw:1364264834069:dw
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
The LCM would be : 2(a+c)(ac)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
let's work the problem a different way and not factorize, and get the denominators the same
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Yes , that would be easy for u.
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Well which denominator you want to be changed
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
You're way is not what we were taught in class and is confusing me. 3m + 6
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Sorry, ok let us change 3(m+2)
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
Would you try that for once?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
to change the denominator ?
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
ok! I have first denominator as (m+2)(m2) and other one as 3(m+2) I want to make 3(m+2) = (m+2)(m2) For that I think I should multiply 3(m+2) by \(\cfrac{(m2)}{3}\)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
where did you get m  2 over 3
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
don't jump ahead, it feels like you are just picking random numbers and variable from the problem
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
Are you all clear now, Firejay?
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
kind of would you explain it the same way
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
Do you want to talk about the original problem or what?
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
It feels like I am being taught a whole different then I learned it in class
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
I just want to make sure we are talking about the right problem. Is this it:
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
When you add fractions you need to have the denominators the same. So we have to build the common denominator.
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
@mathslover you did good though! :D
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
For the first denominator we need the factors m2 and m+2. For the second denominator we need the factors 3 and m+2. But we already have m+2. So the 3 factors we need are 3(m2)(m+2)
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
Are you with me so far?
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
And finally: dw:1364266416514:dw
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
does it matter which order the m  2 or m + 2 goes
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
I put 5m  4 over 3(m + 2)(m  2)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
How would you type 33.) y over y + 3 () 6y over y^2  9 in Wolframalpha
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
\[\frac{y}{y+3}\frac{6y}{y^29}\]
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
For wolf: y/(y+3)(6y)/(y^29)
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
which of the alternative forms are the answer
 one year ago

MertsjBest ResponseYou've already chosen the best response.1
That's the abbreviated version.
 one year ago

Firejay5Best ResponseYou've already chosen the best response.0
is it the first, second, or third one
 one year ago
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