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Firejay5
 3 years ago
Simplify Each Expression. Show work and explain it.
32. m over m^2  4 + 2 over 3m + 6
Firejay5
 3 years ago
Simplify Each Expression. Show work and explain it. 32. m over m^2  4 + 2 over 3m + 6

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Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0Well on #32, I am having trouble multiplying the denominators to make them the same

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0"m over m^2  4 + 2 over 3m + 6" \[ \frac{m}{m^24}+\frac{2}{3m+6} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just use this: \[ \frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think the + is separating two fractions.

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0can you do it with me and then I'll do 33.) my self

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0can we get back to the problem

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0the example he gave isn't going nowhere for me

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let \(b=m^24\) and \(d=3m+6\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \frac{m}{m^24}+\frac{2}{3m+6}=\frac{(m)(3m+6)+(2)(m^24)}{(m^24)(3m+6)} \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Firejay5 Do you see the pattern?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0Yes? Kind of how did you get that

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0I need full out steps, like getting the denominators equal, etc.

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0@Mertsj could you help with that

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1hmn . \[\frac{m}{m^24}+\frac{2}{3m+6}\] Well I think that it would be Ok to factorize both denominators

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Yes. mathslover will be able to show you.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{m^24}\) is in the form of \(a^2b^2\) \(a^2b^2 = (a+b)(ab)\) Use the above stated identity to factorize \(m^24 \) .

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Can you factor \(m^24\) @Firejay5 ?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Can you tell me what would be the factorized form for \(x^24\) ?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Great! So \(x^24 = \color{blue}{(x+2)(x2)}\) Now. we have the complete question as : \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{3m+6}\)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Now take 3 common from 3m + 6. What you get?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0I did the other factorization as well

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Great! \(\cfrac{m}{\color{red}{(m+2)(m2)}}+\cfrac{2}{\color{orange}{3(m+2)}}\). Is what we have now.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1LCM of \(\cfrac{1}{a+b} + \cfrac{1}{2(ab)} \) (denominators) is (a+b)(ab)2

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Similarly do that there. we have \((x+2)(x2) \quad\textbf{and}\quad 3(m+2)\) as the denominators

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0it would be 3(m  2) (m + 2)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Yeah . and sorry there for using x on the place of m

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1So I have : 3(m2)(m+2) as LCM can you solve the fraction :

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0so what would it be entered in equation editor

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1I didn't get you,, please explain!

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0type the problem in fraction form of what we have left

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1hmn well it would be hard to say that I have : \(\cfrac{\textbf{yet to come}}{3(m+2)(m2)}\)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1we have to solve numerator now

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0wouldn't the numerator m + 2

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1No! See : \(\cfrac{1}{(a+b)} + \cfrac{2}{(ab)} = \cfrac{1(ab) + 2(a+b)}{(ab)(a+b)}\)

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0how does it work, you should + across

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364264397027:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1See i have LCM as 3(m+2)(m2) I divided LCM by the first fraction's denominator that is (m+2)(m2) to get 3 . Now I multiplied this 3 by the first fractions' numerator that is m

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Wow, finding the LCM is makes it complicated.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Similarly for the second one.. I have LCM as 3(m+2)(m2) I divided this LCM by the denominator of the second fraction 3(m+2) \(\cfrac{\cancel{3(m+2)} (m2)}{\cancel{3(m+2)} }\)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Does that mean you don't get it @Firejay5 ?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0are the denominators the same

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364264678904:dw

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0whatever you multiply to the bottom, you must do to the top

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0work the problem a whole different way

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364264834069:dw

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1The LCM would be : 2(a+c)(ac)

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0let's work the problem a different way and not factorize, and get the denominators the same

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Yes , that would be easy for u.

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Well which denominator you want to be changed

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0You're way is not what we were taught in class and is confusing me. 3m + 6

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Sorry, ok let us change 3(m+2)

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Would you try that for once?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1to change the denominator ?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1ok! I have first denominator as (m+2)(m2) and other one as 3(m+2) I want to make 3(m+2) = (m+2)(m2) For that I think I should multiply 3(m+2) by \(\cfrac{(m2)}{3}\)

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0where did you get m  2 over 3

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0don't jump ahead, it feels like you are just picking random numbers and variable from the problem

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Are you all clear now, Firejay?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0kind of would you explain it the same way

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1Do you want to talk about the original problem or what?

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0It feels like I am being taught a whole different then I learned it in class

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1I just want to make sure we are talking about the right problem. Is this it:

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1When you add fractions you need to have the denominators the same. So we have to build the common denominator.

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0@mathslover you did good though! :D

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1For the first denominator we need the factors m2 and m+2. For the second denominator we need the factors 3 and m+2. But we already have m+2. So the 3 factors we need are 3(m2)(m+2)

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1And finally: dw:1364266416514:dw

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0does it matter which order the m  2 or m + 2 goes

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0I put 5m  4 over 3(m + 2)(m  2)

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0How would you type 33.) y over y + 3 () 6y over y^2  9 in Wolframalpha

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{y}{y+3}\frac{6y}{y^29}\]

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1For wolf: y/(y+3)(6y)/(y^29)

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0which of the alternative forms are the answer

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1That's the abbreviated version.

Firejay5
 3 years ago
Best ResponseYou've already chosen the best response.0is it the first, second, or third one
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