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julia_copen
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 7 }{ \sqrt{45} }\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1maybe before you do that, note that \(45=9\times 5\) and so \(\sqrt{45}=\sqrt{9\times 5}=\sqrt{9}\sqrt{5}=3\sqrt{5}\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1then \[\frac{ 7 }{ \sqrt{45} }=\frac{7}{3\sqrt{5}}\]and now you only need to multiply top and bottom by \(\sqrt{5}\) to remove the radical from the denominator

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1@julia_copen you got this or you need the steps?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1lets start with \[\frac{7}{3\sqrt{5}}\] your job is to get the radical out of the denominator, so multiply top and bottom by \(\sqrt 5\) you get \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1typo there, meant \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{7\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1final answer is \(\frac{7\sqrt{5}}{15}\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1another quick example \[\frac{4}{\sqrt{3}}=\frac{4}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}=\frac{4\sqrt{3}}{3}\]

julia_copen
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much! Me and my friend were having a hard time trying to understand how to break it down.

julia_copen
 one year ago
Best ResponseYou've already chosen the best response.0can you help me with another?

julia_copen
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{75z} }\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1is the \(z\) inside the radical?

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1ok the idea is to see if the number is the product of some "perfect square" so in this case \(75=25\times 3\) making \[\sqrt{75}=\sqrt{25}\sqrt{3}=5\sqrt{3}\] so star with \[\frac{1}{5\sqrt{3z}}\] and then multiply top and bottom by \(\sqrt{3z}\)

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you get \[\frac{1}{5\sqrt{3z}}\times \frac{\sqrt{3z}}{\sqrt{3z}}=\frac{\sqrt{3z}}{15z}\]

julia_copen
 one year ago
Best ResponseYou've already chosen the best response.0Okay I see. It's always difficult in the beginning for me.

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you will get used to it, (and then probably forget it because it is not really that useful) but in any case it gets easier
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