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julia_copen
 2 years ago
Can someone help me with this radical?
julia_copen
 2 years ago
Can someone help me with this radical?

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julia_copen
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 7 }{ \sqrt{45} }\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1maybe before you do that, note that \(45=9\times 5\) and so \(\sqrt{45}=\sqrt{9\times 5}=\sqrt{9}\sqrt{5}=3\sqrt{5}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1then \[\frac{ 7 }{ \sqrt{45} }=\frac{7}{3\sqrt{5}}\]and now you only need to multiply top and bottom by \(\sqrt{5}\) to remove the radical from the denominator

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1@julia_copen you got this or you need the steps?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1lets start with \[\frac{7}{3\sqrt{5}}\] your job is to get the radical out of the denominator, so multiply top and bottom by \(\sqrt 5\) you get \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1typo there, meant \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{7\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1final answer is \(\frac{7\sqrt{5}}{15}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1another quick example \[\frac{4}{\sqrt{3}}=\frac{4}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}=\frac{4\sqrt{3}}{3}\]

julia_copen
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks so much! Me and my friend were having a hard time trying to understand how to break it down.

julia_copen
 2 years ago
Best ResponseYou've already chosen the best response.0can you help me with another?

julia_copen
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{75z} }\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1is the \(z\) inside the radical?

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1ok the idea is to see if the number is the product of some "perfect square" so in this case \(75=25\times 3\) making \[\sqrt{75}=\sqrt{25}\sqrt{3}=5\sqrt{3}\] so star with \[\frac{1}{5\sqrt{3z}}\] and then multiply top and bottom by \(\sqrt{3z}\)

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you get \[\frac{1}{5\sqrt{3z}}\times \frac{\sqrt{3z}}{\sqrt{3z}}=\frac{\sqrt{3z}}{15z}\]

julia_copen
 2 years ago
Best ResponseYou've already chosen the best response.0Okay I see. It's always difficult in the beginning for me.

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1you will get used to it, (and then probably forget it because it is not really that useful) but in any case it gets easier
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