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julia_copenBest ResponseYou've already chosen the best response.0
\[\frac{ 7 }{ \sqrt{45} }\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
maybe before you do that, note that \(45=9\times 5\) and so \(\sqrt{45}=\sqrt{9\times 5}=\sqrt{9}\sqrt{5}=3\sqrt{5}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
then \[\frac{ 7 }{ \sqrt{45} }=\frac{7}{3\sqrt{5}}\]and now you only need to multiply top and bottom by \(\sqrt{5}\) to remove the radical from the denominator
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
@julia_copen you got this or you need the steps?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
lets start with \[\frac{7}{3\sqrt{5}}\] your job is to get the radical out of the denominator, so multiply top and bottom by \(\sqrt 5\) you get \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
typo there, meant \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{7\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
final answer is \(\frac{7\sqrt{5}}{15}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
another quick example \[\frac{4}{\sqrt{3}}=\frac{4}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}=\frac{4\sqrt{3}}{3}\]
 one year ago

julia_copenBest ResponseYou've already chosen the best response.0
Thanks so much! Me and my friend were having a hard time trying to understand how to break it down.
 one year ago

julia_copenBest ResponseYou've already chosen the best response.0
can you help me with another?
 one year ago

julia_copenBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{ \sqrt{75z} }\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
is the \(z\) inside the radical?
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
ok the idea is to see if the number is the product of some "perfect square" so in this case \(75=25\times 3\) making \[\sqrt{75}=\sqrt{25}\sqrt{3}=5\sqrt{3}\] so star with \[\frac{1}{5\sqrt{3z}}\] and then multiply top and bottom by \(\sqrt{3z}\)
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you get \[\frac{1}{5\sqrt{3z}}\times \frac{\sqrt{3z}}{\sqrt{3z}}=\frac{\sqrt{3z}}{15z}\]
 one year ago

julia_copenBest ResponseYou've already chosen the best response.0
Okay I see. It's always difficult in the beginning for me.
 one year ago

satellite73Best ResponseYou've already chosen the best response.1
you will get used to it, (and then probably forget it because it is not really that useful) but in any case it gets easier
 one year ago
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