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anonymous
 3 years ago
Can someone help me with this radical?
anonymous
 3 years ago
Can someone help me with this radical?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 7 }{ \sqrt{45} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0maybe before you do that, note that \(45=9\times 5\) and so \(\sqrt{45}=\sqrt{9\times 5}=\sqrt{9}\sqrt{5}=3\sqrt{5}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then \[\frac{ 7 }{ \sqrt{45} }=\frac{7}{3\sqrt{5}}\]and now you only need to multiply top and bottom by \(\sqrt{5}\) to remove the radical from the denominator

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@julia_copen you got this or you need the steps?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lets start with \[\frac{7}{3\sqrt{5}}\] your job is to get the radical out of the denominator, so multiply top and bottom by \(\sqrt 5\) you get \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0typo there, meant \[\frac{7}{3\sqrt{5}}\times \frac{\sqrt{5}}{\sqrt{5}}=\frac{7\sqrt{5}}{3\sqrt{5}\sqrt{5}}=\frac{7\sqrt{5}}{3\times 5}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0final answer is \(\frac{7\sqrt{5}}{15}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0another quick example \[\frac{4}{\sqrt{3}}=\frac{4}{\sqrt{3}}\times \frac{\sqrt{3}}{\sqrt{3}}=\frac{4\sqrt{3}}{3}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks so much! Me and my friend were having a hard time trying to understand how to break it down.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you help me with another?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{ \sqrt{75z} }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is the \(z\) inside the radical?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok the idea is to see if the number is the product of some "perfect square" so in this case \(75=25\times 3\) making \[\sqrt{75}=\sqrt{25}\sqrt{3}=5\sqrt{3}\] so star with \[\frac{1}{5\sqrt{3z}}\] and then multiply top and bottom by \(\sqrt{3z}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you get \[\frac{1}{5\sqrt{3z}}\times \frac{\sqrt{3z}}{\sqrt{3z}}=\frac{\sqrt{3z}}{15z}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Okay I see. It's always difficult in the beginning for me.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you will get used to it, (and then probably forget it because it is not really that useful) but in any case it gets easier
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