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jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
what's your question
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
Hang on a second
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
ok
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
I have to draw it lol
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you're fine, no worries
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
that's definitely the best option instead of describing it in words
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
It isn't working. I have no idea what to do.
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
dw:1364269301720:dw
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
ok one sec
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
OK my drawing sucks but this is it.
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
thanks, and your drawing is perfect, no worries
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you need to rationalize the denominator, so you need to multiply top and bottom by \[\Large 10\sqrt{2} + \sqrt{10}\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Doing so will give you \[\Large \frac{5\sqrt{2}+\sqrt{10}}{10\sqrt{2}  \sqrt{10}}\] \[\Large \frac{(5\sqrt{2}+\sqrt{10})((10\sqrt{2} + \sqrt{10}))}{(10\sqrt{2}  \sqrt{10})(10\sqrt{2} + \sqrt{10})}\] Do you know what to do from here?
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
No this is where I got lost.
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
ok you would use the difference of squares rule to expand out the denominator \[\Large (10\sqrt{2}  \sqrt{10})(10\sqrt{2} + \sqrt{10})\] \[\Large (10\sqrt{2})^2  (\sqrt{10})^2\] \[\Large 10^2*(\sqrt{2})^2  (\sqrt{10})^2\] \[\Large 100*2  10\] \[\Large 200  10\] \[\Large 190\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
So \[\Large \frac{(5\sqrt{2}+\sqrt{10})((10\sqrt{2} + \sqrt{10}))}{(10\sqrt{2}  \sqrt{10})(10\sqrt{2} + \sqrt{10})}\] turns into \[\Large \frac{(5\sqrt{2}+\sqrt{10})((10\sqrt{2} + \sqrt{10}))}{190}\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
You just need to expand out the numerator, then you're done
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
Doing that will give you \[\Large (5\sqrt{2}+\sqrt{10})(10\sqrt{2} + \sqrt{10})\] \[\Large 5\sqrt{2}(10\sqrt{2} + \sqrt{10})+\sqrt{10}(10\sqrt{2} + \sqrt{10})\] \[\Large 5\sqrt{2}*10\sqrt{2} + 5\sqrt{2}*\sqrt{10}+\sqrt{10}*10\sqrt{2} + \sqrt{10}*\sqrt{10}\] \[\Large 100 + 5\sqrt{20}+10\sqrt{20} + 10\] \[\Large 110 + 15\sqrt{20}\] \[\Large 110 + 15\sqrt{4*5}\] \[\Large 110 + 15\sqrt{4}*\sqrt{5}\] \[\Large 110 + 15*2*\sqrt{5}\] \[\Large 110 + 30*\sqrt{5}\]
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
So \[\Large \frac{(5\sqrt{2}+\sqrt{10})((10\sqrt{2} + \sqrt{10}))}{190}\] turns into \[\Large \frac{110 + 30*\sqrt{5}}{190}\] I guess from here you can divide each term by 10 to get \[\Large \frac{11 + 3\sqrt{5}}{19}\] and you're done
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
So this shows us that \[\Large \frac{5\sqrt{2}+\sqrt{10}}{10\sqrt{2}  \sqrt{10}} =\frac{11 + 3\sqrt{5}}{19}\]
 one year ago

julia_copen Group TitleBest ResponseYou've already chosen the best response.0
Neat. You explained it so well! I wouldn't have been able to foil that like you did. Thanks!
 one year ago

jim_thompson5910 Group TitleBest ResponseYou've already chosen the best response.1
you're welcome
 one year ago
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