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Dido525
 one year ago
Best ResponseYou've already chosen the best response.1I think it's a elliptic paraboloid but I am not sure...

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Just looking at the cross sections.

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1its either one of the bottom two graphs, i know that

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1I think it's the bottom left one.

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1But I am not sure :/ .

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1What the heck is that shape even called? >.>

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2+z^2 = sphere\]

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Really? Isn't x^2+y^2+z^2= r a sphere?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1you need y^2 for sphere

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1would it just be a cylinder

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1No. The cross sections are parabolas so there is no way it's a cylinder.

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2+z^2 = 7\] is a circle :)

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1I know but... ;_; ... I thought the cross sections would be parabolas :/ .

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1the hare lost the race :P

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1which is again why i am not sure if it is the bottom left or the bottom right

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1K, so it the the bottom right apparantly : / .

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Because it's not like with translate the circle.

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1i guess since its missing the \(y^2\)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1why not two parabolas?

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1you mean a hyperbola? lol

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1It cannot be a hyperbola. No subtraction term appears.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Well if I take z=0 then we get x^2=7 which is a parabola.

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0well x^2+y^2=7 is a circle.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1nawwww… even if you drew just a 2D circle, in microscopic view it is still "cylindrical" in shape

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1nincompoop get your wise self outta here :P

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Well I DO AGREE it is indeed a circle about the xz axis but how does that make it a cylinder? :/ .

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0Cylindrical coordinates are a generalization of twodimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0check wolfram.com

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1nice copypasting, dude! :D

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2

yummydum
 one year ago
Best ResponseYou've already chosen the best response.1jk jk...yea wolfram does say that it is a circle

some_someone
 one year ago
Best ResponseYou've already chosen the best response.0@yummydum i know right, thnx bro :)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1the cylinders that we know are just blownup circles

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1What a stupid definition...

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1oh there's the definition lol

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1I don't like all these coordinate systems :/ .

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1I don't see how... Just stick to rectangular coordinates :/ .

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1Thanks guys for all the help :) .

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1you mean just 2D? awwww do you prefer them pixelated too? L M A O :P

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.1don't be sad… the knowledge you will acquire is transferrable to different physical sciences.

Dido525
 one year ago
Best ResponseYou've already chosen the best response.1As long as it's applicable to engineering...
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