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Dido525

  • 2 years ago

Surface geometry help?

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  1. Dido525
    • 2 years ago
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  2. Dido525
    • 2 years ago
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    I think it's a elliptic paraboloid but I am not sure...

  3. Dido525
    • 2 years ago
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    Just looking at the cross sections.

  4. yummydum
    • 2 years ago
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    its either one of the bottom two graphs, i know that

  5. Dido525
    • 2 years ago
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    I think it's the bottom left one.

  6. Dido525
    • 2 years ago
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    But I am not sure :/ .

  7. yummydum
    • 2 years ago
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    yea same here

  8. Dido525
    • 2 years ago
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    What the heck is that shape even called? >.>

  9. nincompoop
    • 2 years ago
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    \[x^2+z^2 = sphere\]

  10. nincompoop
    • 2 years ago
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    my bad

  11. Dido525
    • 2 years ago
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    Really? Isn't x^2+y^2+z^2= r a sphere?

  12. nincompoop
    • 2 years ago
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    you need y^2 for sphere

  13. Dido525
    • 2 years ago
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    Yeah :P .

  14. yummydum
    • 2 years ago
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    would it just be a cylinder

  15. Dido525
    • 2 years ago
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    No. The cross sections are parabolas so there is no way it's a cylinder.

  16. nincompoop
    • 2 years ago
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    no just a circle

  17. some_someone
    • 2 years ago
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    \[x^2+z^2 = 7\] is a circle :)

  18. Dido525
    • 2 years ago
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    I know but... ;_; ... I thought the cross sections would be parabolas :/ .

  19. nincompoop
    • 2 years ago
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    the hare lost the race :P

  20. yummydum
    • 2 years ago
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    which is again why i am not sure if it is the bottom left or the bottom right

  21. Dido525
    • 2 years ago
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    K, so it the the bottom right apparantly : / .

  22. Dido525
    • 2 years ago
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    Not sure why though.

  23. Dido525
    • 2 years ago
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    Because it's not like with translate the circle.

  24. yummydum
    • 2 years ago
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    i guess since its missing the \(y^2\)

  25. nincompoop
    • 2 years ago
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    why oh why?

  26. nincompoop
    • 2 years ago
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    why not two parabolas?

  27. yummydum
    • 2 years ago
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    you mean a hyperbola? lol

  28. Dido525
    • 2 years ago
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    It cannot be a hyperbola. No subtraction term appears.

  29. yummydum
    • 2 years ago
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    exactly :)

  30. nincompoop
    • 2 years ago
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    wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?

  31. Dido525
    • 2 years ago
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    Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .

  32. yummydum
    • 2 years ago
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    hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder

  33. Dido525
    • 2 years ago
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    Well if I take z=0 then we get x^2=7 which is a parabola.

  34. some_someone
    • 2 years ago
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    well x^2+y^2=7 is a circle.

  35. nincompoop
    • 2 years ago
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    nawwww… even if you drew just a 2-D circle, in microscopic view it is still "cylindrical" in shape

  36. yummydum
    • 2 years ago
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    nincompoop get your wise self outta here :P

  37. Dido525
    • 2 years ago
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    Well I DO AGREE it is indeed a circle about the x-z axis but how does that make it a cylinder? :/ .

  38. some_someone
    • 2 years ago
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    Cylindrical coordinates are a generalization of two-dimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.

  39. some_someone
    • 2 years ago
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    check wolfram.com

  40. yummydum
    • 2 years ago
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    nice copy-pasting, dude! :D

  41. some_someone
    • 2 years ago
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    https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2

  42. yummydum
    • 2 years ago
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    jk jk...yea wolfram does say that it is a circle

  43. some_someone
    • 2 years ago
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    @yummydum i know right, thnx bro :)

  44. nincompoop
    • 2 years ago
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    the cylinders that we know are just blown-up circles

  45. Dido525
    • 2 years ago
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    What a stupid definition...

  46. nincompoop
    • 2 years ago
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    oh there's the definition lol

  47. Dido525
    • 2 years ago
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    I don't like all these coordinate systems :/ .

  48. nincompoop
    • 2 years ago
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    they are useful

  49. Dido525
    • 2 years ago
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    I don't see how... Just stick to rectangular coordinates :/ .

  50. Dido525
    • 2 years ago
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    Thanks guys for all the help :) .

  51. nincompoop
    • 2 years ago
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    you mean just 2-D? awwww do you prefer them pixelated too? L M A O :P

  52. Dido525
    • 2 years ago
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    :( .

  53. nincompoop
    • 2 years ago
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    don't be sad… the knowledge you will acquire is transferrable to different physical sciences.

  54. Dido525
    • 2 years ago
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    As long as it's applicable to engineering...

  55. nincompoop
    • 2 years ago
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    you bet

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