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Dido525

  • one year ago

Surface geometry help?

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  1. Dido525
    • one year ago
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  2. Dido525
    • one year ago
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    I think it's a elliptic paraboloid but I am not sure...

  3. Dido525
    • one year ago
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    Just looking at the cross sections.

  4. yummydum
    • one year ago
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    its either one of the bottom two graphs, i know that

  5. Dido525
    • one year ago
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    I think it's the bottom left one.

  6. Dido525
    • one year ago
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    But I am not sure :/ .

  7. yummydum
    • one year ago
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    yea same here

  8. Dido525
    • one year ago
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    What the heck is that shape even called? >.>

  9. nincompoop
    • one year ago
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    \[x^2+z^2 = sphere\]

  10. nincompoop
    • one year ago
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    my bad

  11. Dido525
    • one year ago
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    Really? Isn't x^2+y^2+z^2= r a sphere?

  12. nincompoop
    • one year ago
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    you need y^2 for sphere

  13. Dido525
    • one year ago
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    Yeah :P .

  14. yummydum
    • one year ago
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    would it just be a cylinder

  15. Dido525
    • one year ago
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    No. The cross sections are parabolas so there is no way it's a cylinder.

  16. nincompoop
    • one year ago
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    no just a circle

  17. some_someone
    • one year ago
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    \[x^2+z^2 = 7\] is a circle :)

  18. Dido525
    • one year ago
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    I know but... ;_; ... I thought the cross sections would be parabolas :/ .

  19. nincompoop
    • one year ago
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    the hare lost the race :P

  20. yummydum
    • one year ago
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    which is again why i am not sure if it is the bottom left or the bottom right

  21. Dido525
    • one year ago
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    K, so it the the bottom right apparantly : / .

  22. Dido525
    • one year ago
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    Not sure why though.

  23. Dido525
    • one year ago
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    Because it's not like with translate the circle.

  24. yummydum
    • one year ago
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    i guess since its missing the \(y^2\)

  25. nincompoop
    • one year ago
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    why oh why?

  26. nincompoop
    • one year ago
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    why not two parabolas?

  27. yummydum
    • one year ago
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    you mean a hyperbola? lol

  28. Dido525
    • one year ago
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    It cannot be a hyperbola. No subtraction term appears.

  29. yummydum
    • one year ago
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    exactly :)

  30. nincompoop
    • one year ago
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    wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?

  31. Dido525
    • one year ago
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    Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .

  32. yummydum
    • one year ago
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    hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder

  33. Dido525
    • one year ago
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    Well if I take z=0 then we get x^2=7 which is a parabola.

  34. some_someone
    • one year ago
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    well x^2+y^2=7 is a circle.

  35. nincompoop
    • one year ago
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    nawwww… even if you drew just a 2-D circle, in microscopic view it is still "cylindrical" in shape

  36. yummydum
    • one year ago
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    nincompoop get your wise self outta here :P

  37. Dido525
    • one year ago
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    Well I DO AGREE it is indeed a circle about the x-z axis but how does that make it a cylinder? :/ .

  38. some_someone
    • one year ago
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    Cylindrical coordinates are a generalization of two-dimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.

  39. some_someone
    • one year ago
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    check wolfram.com

  40. yummydum
    • one year ago
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    nice copy-pasting, dude! :D

  41. some_someone
    • one year ago
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    https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2

  42. yummydum
    • one year ago
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    jk jk...yea wolfram does say that it is a circle

  43. some_someone
    • one year ago
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    @yummydum i know right, thnx bro :)

  44. nincompoop
    • one year ago
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    the cylinders that we know are just blown-up circles

  45. Dido525
    • one year ago
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    What a stupid definition...

  46. nincompoop
    • one year ago
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    oh there's the definition lol

  47. Dido525
    • one year ago
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    I don't like all these coordinate systems :/ .

  48. nincompoop
    • one year ago
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    they are useful

  49. Dido525
    • one year ago
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    I don't see how... Just stick to rectangular coordinates :/ .

  50. Dido525
    • one year ago
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    Thanks guys for all the help :) .

  51. nincompoop
    • one year ago
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    you mean just 2-D? awwww do you prefer them pixelated too? L M A O :P

  52. Dido525
    • one year ago
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    :( .

  53. nincompoop
    • one year ago
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    don't be sad… the knowledge you will acquire is transferrable to different physical sciences.

  54. Dido525
    • one year ago
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    As long as it's applicable to engineering...

  55. nincompoop
    • one year ago
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    you bet

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