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anonymous
 3 years ago
Surface geometry help?
anonymous
 3 years ago
Surface geometry help?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think it's a elliptic paraboloid but I am not sure...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Just looking at the cross sections.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0its either one of the bottom two graphs, i know that

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I think it's the bottom left one.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0But I am not sure :/ .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What the heck is that shape even called? >.>

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1\[x^2+z^2 = sphere\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Really? Isn't x^2+y^2+z^2= r a sphere?

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1you need y^2 for sphere

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0would it just be a cylinder

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0No. The cross sections are parabolas so there is no way it's a cylinder.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[x^2+z^2 = 7\] is a circle :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I know but... ;_; ... I thought the cross sections would be parabolas :/ .

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1the hare lost the race :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0which is again why i am not sure if it is the bottom left or the bottom right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0K, so it the the bottom right apparantly : / .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because it's not like with translate the circle.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i guess since its missing the \(y^2\)

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1why not two parabolas?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you mean a hyperbola? lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0It cannot be a hyperbola. No subtraction term appears.

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well if I take z=0 then we get x^2=7 which is a parabola.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well x^2+y^2=7 is a circle.

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1nawwww… even if you drew just a 2D circle, in microscopic view it is still "cylindrical" in shape

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nincompoop get your wise self outta here :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Well I DO AGREE it is indeed a circle about the xz axis but how does that make it a cylinder? :/ .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Cylindrical coordinates are a generalization of twodimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0nice copypasting, dude! :D

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0jk jk...yea wolfram does say that it is a circle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@yummydum i know right, thnx bro :)

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1the cylinders that we know are just blownup circles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What a stupid definition...

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1oh there's the definition lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't like all these coordinate systems :/ .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I don't see how... Just stick to rectangular coordinates :/ .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks guys for all the help :) .

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1you mean just 2D? awwww do you prefer them pixelated too? L M A O :P

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1don't be sad… the knowledge you will acquire is transferrable to different physical sciences.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0As long as it's applicable to engineering...
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