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Dido525Best ResponseYou've already chosen the best response.1
I think it's a elliptic paraboloid but I am not sure...
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Just looking at the cross sections.
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
its either one of the bottom two graphs, i know that
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
I think it's the bottom left one.
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
But I am not sure :/ .
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
What the heck is that shape even called? >.>
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
\[x^2+z^2 = sphere\]
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Really? Isn't x^2+y^2+z^2= r a sphere?
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
you need y^2 for sphere
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
would it just be a cylinder
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
No. The cross sections are parabolas so there is no way it's a cylinder.
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
\[x^2+z^2 = 7\] is a circle :)
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
I know but... ;_; ... I thought the cross sections would be parabolas :/ .
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
the hare lost the race :P
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
which is again why i am not sure if it is the bottom left or the bottom right
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
K, so it the the bottom right apparantly : / .
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Because it's not like with translate the circle.
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
i guess since its missing the \(y^2\)
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
why not two parabolas?
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
you mean a hyperbola? lol
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
It cannot be a hyperbola. No subtraction term appears.
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Well if I take z=0 then we get x^2=7 which is a parabola.
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
well x^2+y^2=7 is a circle.
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
nawwww… even if you drew just a 2D circle, in microscopic view it is still "cylindrical" in shape
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
nincompoop get your wise self outta here :P
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Well I DO AGREE it is indeed a circle about the xz axis but how does that make it a cylinder? :/ .
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
Cylindrical coordinates are a generalization of twodimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
check wolfram.com
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
nice copypasting, dude! :D
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2
 one year ago

yummydumBest ResponseYou've already chosen the best response.1
jk jk...yea wolfram does say that it is a circle
 one year ago

some_someoneBest ResponseYou've already chosen the best response.0
@yummydum i know right, thnx bro :)
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
the cylinders that we know are just blownup circles
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
What a stupid definition...
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
oh there's the definition lol
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
I don't like all these coordinate systems :/ .
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
I don't see how... Just stick to rectangular coordinates :/ .
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
Thanks guys for all the help :) .
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
you mean just 2D? awwww do you prefer them pixelated too? L M A O :P
 one year ago

nincompoopBest ResponseYou've already chosen the best response.1
don't be sad… the knowledge you will acquire is transferrable to different physical sciences.
 one year ago

Dido525Best ResponseYou've already chosen the best response.1
As long as it's applicable to engineering...
 one year ago
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