anonymous
  • anonymous
Surface geometry help?
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
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anonymous
  • anonymous
I think it's a elliptic paraboloid but I am not sure...
anonymous
  • anonymous
Just looking at the cross sections.

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anonymous
  • anonymous
its either one of the bottom two graphs, i know that
anonymous
  • anonymous
I think it's the bottom left one.
anonymous
  • anonymous
But I am not sure :/ .
anonymous
  • anonymous
yea same here
anonymous
  • anonymous
What the heck is that shape even called? >.>
nincompoop
  • nincompoop
\[x^2+z^2 = sphere\]
nincompoop
  • nincompoop
my bad
anonymous
  • anonymous
Really? Isn't x^2+y^2+z^2= r a sphere?
nincompoop
  • nincompoop
you need y^2 for sphere
anonymous
  • anonymous
Yeah :P .
anonymous
  • anonymous
would it just be a cylinder
anonymous
  • anonymous
No. The cross sections are parabolas so there is no way it's a cylinder.
nincompoop
  • nincompoop
no just a circle
anonymous
  • anonymous
\[x^2+z^2 = 7\] is a circle :)
anonymous
  • anonymous
I know but... ;_; ... I thought the cross sections would be parabolas :/ .
nincompoop
  • nincompoop
the hare lost the race :P
anonymous
  • anonymous
which is again why i am not sure if it is the bottom left or the bottom right
anonymous
  • anonymous
K, so it the the bottom right apparantly : / .
anonymous
  • anonymous
Not sure why though.
anonymous
  • anonymous
Because it's not like with translate the circle.
anonymous
  • anonymous
i guess since its missing the \(y^2\)
nincompoop
  • nincompoop
why oh why?
nincompoop
  • nincompoop
why not two parabolas?
anonymous
  • anonymous
you mean a hyperbola? lol
anonymous
  • anonymous
It cannot be a hyperbola. No subtraction term appears.
anonymous
  • anonymous
exactly :)
nincompoop
  • nincompoop
wow I suck at "surface" geometry LOL so it is a circle yes? why not pick the one with a circle in the first place?
anonymous
  • anonymous
Because I assumed the cross sections would be parabolas so it did not seem logical to pick a cylinder :/ .
anonymous
  • anonymous
hey wouldnt it have to be x^2+y^2=7 to be parabolic? i think thats why its a cylinder
anonymous
  • anonymous
Well if I take z=0 then we get x^2=7 which is a parabola.
anonymous
  • anonymous
well x^2+y^2=7 is a circle.
nincompoop
  • nincompoop
nawwww… even if you drew just a 2-D circle, in microscopic view it is still "cylindrical" in shape
anonymous
  • anonymous
nincompoop get your wise self outta here :P
anonymous
  • anonymous
Well I DO AGREE it is indeed a circle about the x-z axis but how does that make it a cylinder? :/ .
anonymous
  • anonymous
Cylindrical coordinates are a generalization of two-dimensional polar coordinates to three dimensions by superposing a height (z) axis. Unfortunately, there are a number of different notations used for the other two coordinates. Either r or rho is used to refer to the radial coordinate and either phi or theta to the azimuthal coordinates. Arfken, for instance, uses (rho, phi, z), while Beyer uses (r, theta, z). In this work, the notation (r, theta, z) is used. The following table summarizes notational conventions used by a number of authors.
anonymous
  • anonymous
check wolfram.com
anonymous
  • anonymous
nice copy-pasting, dude! :D
anonymous
  • anonymous
https://www.wolframalpha.com/input/?i=cylindrical+coordinates&lk=4&num=2
anonymous
  • anonymous
jk jk...yea wolfram does say that it is a circle
anonymous
  • anonymous
@yummydum i know right, thnx bro :)
nincompoop
  • nincompoop
the cylinders that we know are just blown-up circles
anonymous
  • anonymous
What a stupid definition...
nincompoop
  • nincompoop
oh there's the definition lol
anonymous
  • anonymous
I don't like all these coordinate systems :/ .
nincompoop
  • nincompoop
they are useful
anonymous
  • anonymous
I don't see how... Just stick to rectangular coordinates :/ .
anonymous
  • anonymous
Thanks guys for all the help :) .
nincompoop
  • nincompoop
you mean just 2-D? awwww do you prefer them pixelated too? L M A O :P
anonymous
  • anonymous
:( .
nincompoop
  • nincompoop
don't be sad… the knowledge you will acquire is transferrable to different physical sciences.
anonymous
  • anonymous
As long as it's applicable to engineering...
nincompoop
  • nincompoop
you bet

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