A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
In the assifnments from this course on the 1 problem set, in exercise 3 I simply dont understand what I'm doing wrong.
y = 1000  x^2
y' = 2x
I need to find the line that is tangent to y and that also passes through (0,1100).
I get yyo=y'(xo)(xxo)
But i dont know (xo,yo)
Please help
Original question:
3. On the planet Quirk, a cell phone tower is a 100foot pole on top of a green
mound 1000 feet tall whose outline is described by the parabolic equation y = 1000 − x^2
. An ant climbs up the mound starting from ground level (y = 0). At what height y does the ant begin to
see the tower?
anonymous
 3 years ago
In the assifnments from this course on the 1 problem set, in exercise 3 I simply dont understand what I'm doing wrong. y = 1000  x^2 y' = 2x I need to find the line that is tangent to y and that also passes through (0,1100). I get yyo=y'(xo)(xxo) But i dont know (xo,yo) Please help Original question: 3. On the planet Quirk, a cell phone tower is a 100foot pole on top of a green mound 1000 feet tall whose outline is described by the parabolic equation y = 1000 − x^2 . An ant climbs up the mound starting from ground level (y = 0). At what height y does the ant begin to see the tower?

This Question is Closed

Waynex
 3 years ago
Best ResponseYou've already chosen the best response.1There is a nice explanation of the method to solve this at this link: http://math.stackexchange.com/a/137068 The post I linked to has the solution, but it might be helpful to read a few other posts there. Even with that information, the solution might be difficult. I'll help you get there, if needed. By the way, thanks for asking this question. I stumbled on this type of problem a few months back, and just couldn't crack it. That forum post I linked to helped a lot. And I did crack it. When you asked the question, that gave me an opportunity to see if I still remembered it. I vaguely did, but I had to refer back to that forum post lol.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thanks a lot for the post. I just craked it. I'm really happy. It was really just a system because the tangent point belongs to both the tangent line and the curve :D thx a lot man!!

Waynex
 3 years ago
Best ResponseYou've already chosen the best response.1You're welcome. Very true, I haven't tried to solve one that way. It did occur to me that setting it up as a system of equations might be easier than parameterizing a point on the curve.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.