In the assifnments from this course on the 1 problem set, in exercise 3 I simply dont understand what I'm doing wrong.
y = 1000 - x^2
y' = -2x
I need to find the line that is tangent to y and that also passes through (0,1100).
I get y-yo=y'(xo)(x-xo)
But i dont know (xo,yo)
3. On the planet Quirk, a cell phone tower is a 100-foot pole on top of a green
mound 1000 feet tall whose outline is described by the parabolic equation y = 1000 − x^2
. An ant climbs up the mound starting from ground level (y = 0). At what height y does the ant begin to
see the tower?
MIT 18.01 Single Variable Calculus (OCW)
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
There is a nice explanation of the method to solve this at this link: http://math.stackexchange.com/a/137068
The post I linked to has the solution, but it might be helpful to read a few other posts there. Even with that information, the solution might be difficult. I'll help you get there, if needed.
By the way, thanks for asking this question. I stumbled on this type of problem a few months back, and just couldn't crack it. That forum post I linked to helped a lot. And I did crack it. When you asked the question, that gave me an opportunity to see if I still remembered it. I vaguely did, but I had to refer back to that forum post lol.
Thanks a lot for the post. I just craked it. I'm really happy. It was really just a system because the tangent point belongs to both the tangent line and the curve :D thx a lot man!!
Very true, I haven't tried to solve one that way. It did occur to me that setting it up as a system of equations might be easier than parameterizing a point on the curve.