A community for students.
Here's the question you clicked on:
 0 viewing

This Question is Closed

abbie1
 one year ago
Best ResponseYou've already chosen the best response.1@hartnn ?? Can you help me! I have been working on this problem for forever.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1restrictions on values of 'x' right ?

abbie1
 one year ago
Best ResponseYou've already chosen the best response.1Yes I already simplified it and multiplied it together, and this is the end product. But I don't know the restrictions bc it's a complex denominator.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1complex denominator ? denominator = 5 (3x1)^2 right ? restrictions : denominator = 0 so, ''x can't take values for which denominator = 5 (3x1)^2 = 0 so, 3x1 = 0 can you solve this for x ?

abbie1
 one year ago
Best ResponseYou've already chosen the best response.1Oh, so it's 1/3, but what about the 5? And would you write the final answernumerator like 4x^2x+4x1, or (x+1)(4x1)?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1about the 5 : \(5 (3x1)^2=0 \\ \) divide both sides by 5 , 0/5 = 0 \((3x1)^2=0\) take square root, 3x1 = 0 x=1/3 is the restriction. numerator is a polynomial , so in this case it does not play any role.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.