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PLEASE CAN YOU HELP ME? I'm stuck
Simplify the radical expressions
sqrt 7 (sqrt 14 + sqrt 3)
sqrt 45n^5
 one year ago
 one year ago
PLEASE CAN YOU HELP ME? I'm stuck Simplify the radical expressions sqrt 7 (sqrt 14 + sqrt 3) sqrt 45n^5
 one year ago
 one year ago

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mushinniBest ResponseYou've already chosen the best response.0
on the first one I got until here sqrt 7 * sqrt 14 + sqrt 7 * sqrt 3 sqrt 7 * sqrt 7x2 + ......
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
and on the second one until here: sqrt 5*9*n^2*n^2*n = sqrt 5 * sqrt 9 * sqrt n^2 * sqrt n^2 * sqrt n
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
the 1st question is simply \[\sqrt{7} \times \sqrt{14} + \sqrt{7} \times \sqrt{3} = \sqrt{ 7 \times 14} + \sqrt{7 \times 3}\] you need to simplify it the 2nd question \[\sqrt{45n^5} = \sqrt{9n^4 \times 5n} = \sqrt{9n^4} \times \sqrt{5n}\] just simplify
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
so on the fist one was I right?
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
I just missed the sqrt 7x3 right?
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
going back to the 1st question \[\sqrt{7 \times 14} = \sqrt{98} = \sqrt{49 \times 2}\] which can be simplified.
 one year ago

campbell_stBest ResponseYou've already chosen the best response.0
well \[\sqrt{49} \times \sqrt{2} = 7\sqrt{2}\] so the 1st question is \[7\sqrt{2} + \sqrt{21}\] the 2nd question \[\sqrt{9n^4} \times \sqrt{5n} = 3n^2\sqrt{5n}\] hope this makes sense.
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
second question final form. is it. \[3n ^{2} \sqrt{5n}\]
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
oh! ok I busy making the equation haha
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
yes on the second yes it does
 one year ago

mushinniBest ResponseYou've already chosen the best response.0
oh ok! got the firt one
 one year ago
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