## anonymous 3 years ago PLEASE CAN YOU HELP ME? I'm stuck Simplify the radical expressions sqrt 7 (sqrt 14 + sqrt 3) sqrt 45n^5

1. anonymous

on the first one I got until here sqrt 7 * sqrt 14 + sqrt 7 * sqrt 3 sqrt 7 * sqrt 7x2 + ......

2. anonymous

and on the second one until here: sqrt 5*9*n^2*n^2*n = sqrt 5 * sqrt 9 * sqrt n^2 * sqrt n^2 * sqrt n

3. campbell_st

the 1st question is simply $\sqrt{7} \times \sqrt{14} + \sqrt{7} \times \sqrt{3} = \sqrt{ 7 \times 14} + \sqrt{7 \times 3}$ you need to simplify it the 2nd question $\sqrt{45n^5} = \sqrt{9n^4 \times 5n} = \sqrt{9n^4} \times \sqrt{5n}$ just simplify

4. anonymous

so on the fist one was I right?

5. anonymous

I just missed the sqrt 7x3 right?

6. campbell_st

going back to the 1st question $\sqrt{7 \times 14} = \sqrt{98} = \sqrt{49 \times 2}$ which can be simplified.

7. anonymous

into... sqrt 7x2 ?

8. campbell_st

well $\sqrt{49} \times \sqrt{2} = 7\sqrt{2}$ so the 1st question is $7\sqrt{2} + \sqrt{21}$ the 2nd question $\sqrt{9n^4} \times \sqrt{5n} = 3n^2\sqrt{5n}$ hope this makes sense.

9. anonymous

second question final form. is it. $3n ^{2} \sqrt{5n}$

10. anonymous

oh! ok I busy making the equation haha

11. anonymous

yes on the second yes it does

12. campbell_st

13. anonymous

oh ok! got the firt one

14. anonymous

thank you very much!