## Haleyy_Bugg 2 years ago Choose the correct description of the graph of the compound inequality 2x < -12 or x + 3 >= 12 A number line with an open circle on -6, shading to the left, and a closed circle on 9, shading to the right. A number line with a closed circle on -6, shading to the left, and an open circle on 9, shading to the right. A number line with an open circle on -6, a closed circle on 9, and shading in between. A number line with a closed circle on -6, an open circle on 9, and shading in between.

1. Haleyy_Bugg

@Notamathgenius

2. aajugdar

still on this?

3. Notamathgenius

Haleyy, I have no clue o_o sorry o_o

4. Haleyy_Bugg

yes i am .-.

5. aajugdar

first is x<-6

6. aajugdar

so open circle on -6 n shading on left

7. aajugdar

2nd is x>=9

8. aajugdar

so its closed circle n shading to right

9. Haleyy_Bugg

so what do itry to find as to be an answer?

10. aajugdar

hmm consider 1st 1 2x<-12 so x< -12/2 x<-6 so all the terms less than -6 will be included xcept -6 |dw:1364411428556:dw|

11. Haleyy_Bugg

so A?

12. aajugdar

yes

13. Haleyy_Bugg

What is the equation of the line that passes through the points (-2, 1) and (1, 10)? A) 3x - y = -7 B) 3x - y = -5 C) 3x - y = 5 D) x + 3y = -5

14. aajugdar

and 2nd 1 is easy x+3>=12 x>=12-3 x>=9 so all terms greater than or equal to 12 |dw:1364411626234:dw|

15. Haleyy_Bugg

16. aajugdar

put values of (x,y) in equation

17. aajugdar

18. Haleyy_Bugg

to the first one, but what about the second one?

19. aajugdar

A put the values

20. Haleyy_Bugg

idk how.

21. aajugdar

(-2,1) = (x,y) so put x= -2 and y=1

22. aajugdar

3x - y = -7 in this

23. aajugdar

if this doesnt satisfy then check for 2nd option

24. aajugdar

you are supposed to check for (1, 10) too

25. Haleyy_Bugg

okay that just confused me.

26. aajugdar

well then

27. Haleyy_Bugg

yupp