Haleyy_Bugg
Choose the correct description of the graph of the compound inequality
2x < -12 or x + 3 >= 12
A number line with an open circle on -6, shading to the left, and a closed circle on 9, shading to the right.
A number line with a closed circle on -6, shading to the left, and an open circle on 9, shading to the right.
A number line with an open circle on -6, a closed circle on 9, and shading in between.
A number line with a closed circle on -6, an open circle on 9, and shading in between.
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Haleyy_Bugg
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@Notamathgenius
aajugdar
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still on this?
Notamathgenius
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Haleyy, I have no clue o_o sorry o_o
Haleyy_Bugg
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yes i am .-.
aajugdar
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first is x<-6
aajugdar
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so open circle on -6 n shading on left
aajugdar
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2nd is x>=9
aajugdar
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so its closed circle n shading to right
Haleyy_Bugg
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so what do itry to find as to be an answer?
aajugdar
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hmm consider 1st 1
2x<-12
so x< -12/2
x<-6
so all the terms less than -6 will be included xcept -6
|dw:1364411428556:dw|
Haleyy_Bugg
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so A?
aajugdar
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yes
Haleyy_Bugg
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What is the equation of the line that passes through the points (-2, 1) and (1, 10)?
A) 3x - y = -7
B) 3x - y = -5
C) 3x - y = 5
D) x + 3y = -5
aajugdar
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and 2nd 1 is easy
x+3>=12
x>=12-3
x>=9
so all terms greater than or equal to 12
|dw:1364411626234:dw|
Haleyy_Bugg
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but A was the answer?
aajugdar
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put values of (x,y) in equation
aajugdar
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A is the answer
Haleyy_Bugg
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to the first one, but what about the second one?
aajugdar
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A
put the values
Haleyy_Bugg
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idk how.
aajugdar
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(-2,1) = (x,y)
so put x= -2 and y=1
aajugdar
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3x - y = -7
in this
aajugdar
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if this doesnt satisfy
then check for 2nd option
aajugdar
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you are supposed to check for (1, 10) too
Haleyy_Bugg
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okay that just confused me.
aajugdar
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well then
Haleyy_Bugg
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yupp