Choose the correct description of the graph of the compound inequality
2x < -12 or x + 3 >= 12
A number line with an open circle on -6, shading to the left, and a closed circle on 9, shading to the right.
A number line with a closed circle on -6, shading to the left, and an open circle on 9, shading to the right.
A number line with an open circle on -6, a closed circle on 9, and shading in between.
A number line with a closed circle on -6, an open circle on 9, and shading in between.

- anonymous

- jamiebookeater

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- anonymous

- anonymous

still on this?

- Notamathgenius

Haleyy, I have no clue o_o sorry o_o

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## More answers

- anonymous

yes i am .-.

- anonymous

first is x<-6

- anonymous

so open circle on -6 n shading on left

- anonymous

2nd is x>=9

- anonymous

so its closed circle n shading to right

- anonymous

so what do itry to find as to be an answer?

- anonymous

hmm consider 1st 1
2x<-12
so x< -12/2
x<-6
so all the terms less than -6 will be included xcept -6
|dw:1364411428556:dw|

- anonymous

so A?

- anonymous

yes

- anonymous

What is the equation of the line that passes through the points (-2, 1) and (1, 10)?
A) 3x - y = -7
B) 3x - y = -5
C) 3x - y = 5
D) x + 3y = -5

- anonymous

and 2nd 1 is easy
x+3>=12
x>=12-3
x>=9
so all terms greater than or equal to 12
|dw:1364411626234:dw|

- anonymous

but A was the answer?

- anonymous

put values of (x,y) in equation

- anonymous

A is the answer

- anonymous

to the first one, but what about the second one?

- anonymous

A
put the values

- anonymous

idk how.

- anonymous

(-2,1) = (x,y)
so put x= -2 and y=1

- anonymous

3x - y = -7
in this

- anonymous

if this doesnt satisfy
then check for 2nd option

- anonymous

you are supposed to check for (1, 10) too

- anonymous

okay that just confused me.

- anonymous

well then

- anonymous

yupp

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