anonymous
  • anonymous
for section 1H problem 3b: log(y+1)=x^2 + log(y-1) I can't seem to figure out why, when rewritten in the solutions, the x^2 becomes negative. What am I missing?
MIT 18.01 Single Variable Calculus (OCW)
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Could you please copy the original problem? I cant find it on the problem sets nor the exams.
anonymous
  • anonymous
1H-3 Solve the following for y: b) log(y+1)=x2 +log(y−1) this is exactly as it's written here: http://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/1.-differentiation/part-b-implicit-differentiation-and-inverse-functions/problem-set-2/MIT18_01SC_pset1prb.pdf in the solutions, when it is rewritten, somehow the x^2 becomes negative and I can't see why: log(y + 1) − log(y − 1) = −x2 as shown in the solutions here: http://ocw.mit.edu/courses/mathematics/18-01sc-single-variable-calculus-fall-2010/1.-differentiation/part-b-implicit-differentiation-and-inverse-functions/problem-set-2/MIT18_01SC_pset1sol.pdf
anonymous
  • anonymous
I really believe the answer is wrong.Did it 2 times now and the solution for y is: \[y=\frac{ 10^{x ^{2}} +1 }{10^{x ^{2}} -1 }\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
thank you very much! thought I was crazy, but I got that same answer, too! I appreciate the help!
anonymous
  • anonymous
yw :D

Looking for something else?

Not the answer you are looking for? Search for more explanations.