anonymous
  • anonymous
Find the general solution of the given differential equation 2y''+ 2y'+y = 0 Please help me solve this.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
use the characteristic equation, do you know how?
anonymous
  • anonymous
Yes it's just the answer has sine and cosines in it and I don't know how they got it
anonymous
  • anonymous
that's because your answer are complex conjugated solutions. Have you dealt with them before?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
No. All of the other questions were not like that
anonymous
  • anonymous
It's a bit hard to explain the nature of complex numbers and how they apply to Differential Equations in just one post, it's a rather big topic, but if you want, I can link you to Pauls Website where he deals with complex solutions.
anonymous
  • anonymous
just solve it using characterist equation; you should get expoential(like you always do) but with complex power; use euler idenity to get sin/cos
anonymous
  • anonymous
I was looking at it earlier under repeated roots and reduction order but it didn't help
anonymous
  • anonymous
Euler's identity? Yea we didn't cover that. I guess il try looking that up
anonymous
  • anonymous
Thank you both for your help

Looking for something else?

Not the answer you are looking for? Search for more explanations.