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ohno0..0
 2 years ago
Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2.
Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck.
I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?
ohno0..0
 2 years ago
Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2. Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck. I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?

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Anonymous1921
 2 years ago
Best ResponseYou've already chosen the best response.0Given the forces of friction, the masses and acceleration, you can use F = ma.

ohno0..0
 2 years ago
Best ResponseYou've already chosen the best response.0your a fluttering dumbass .

Anonymous1921
 2 years ago
Best ResponseYou've already chosen the best response.0F  T  500 = 1600 * 0.70 F + T 250 = 1200 * 0.70 dw:1364442269773:dw Work out what T and F are.

ohno0..0
 2 years ago
Best ResponseYou've already chosen the best response.0Lol thats the whole point. I don't know how.. i drew the diagram like that just dont know where to go from there.

Anonymous1921
 2 years ago
Best ResponseYou've already chosen the best response.0If you managed to draw the diagram, the rest is easy. You need to apply F = ma to each object. All horizontal forces on the truck are F, T and friction. Just be careful about the direction.

zaphodplaysitsafe
 2 years ago
Best ResponseYou've already chosen the best response.0for the truck  F is the force forwards, T(tension)  imagine this as a rope between truck and trailor. So for truck, the rope (T) is pulling the truck backwards. and friction(opposite to truck's motion) pulling the truck backwards. So we have F  T  frictionofTruck = mass of truck * acceleration of truck F  T  500 = 1600 * 0.7 Now for the trailor, the trailor is moving because of the pull from the rope (T), and the friction is opposing its motion . So, T  frictionOnTrailor = mass of trailor * acceleration Hence T  250 = 1200 * 0.7 so we get T = 250 + 840 = 1090 N Now force is F = T + 500 + 1600*0.7 = 1090 + 500 + 1120 = 2710 N
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