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Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2.
Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck.
I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?
 one year ago
 one year ago
Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2. Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck. I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?
 one year ago
 one year ago

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Anonymous1921Best ResponseYou've already chosen the best response.0
Given the forces of friction, the masses and acceleration, you can use F = ma.
 one year ago

ohno0..0Best ResponseYou've already chosen the best response.0
your a fluttering dumbass .
 one year ago

Anonymous1921Best ResponseYou've already chosen the best response.0
F  T  500 = 1600 * 0.70 F + T 250 = 1200 * 0.70 dw:1364442269773:dw Work out what T and F are.
 one year ago

ohno0..0Best ResponseYou've already chosen the best response.0
Lol thats the whole point. I don't know how.. i drew the diagram like that just dont know where to go from there.
 one year ago

Anonymous1921Best ResponseYou've already chosen the best response.0
If you managed to draw the diagram, the rest is easy. You need to apply F = ma to each object. All horizontal forces on the truck are F, T and friction. Just be careful about the direction.
 one year ago

zaphodplaysitsafeBest ResponseYou've already chosen the best response.0
for the truck  F is the force forwards, T(tension)  imagine this as a rope between truck and trailor. So for truck, the rope (T) is pulling the truck backwards. and friction(opposite to truck's motion) pulling the truck backwards. So we have F  T  frictionofTruck = mass of truck * acceleration of truck F  T  500 = 1600 * 0.7 Now for the trailor, the trailor is moving because of the pull from the rope (T), and the friction is opposing its motion . So, T  frictionOnTrailor = mass of trailor * acceleration Hence T  250 = 1200 * 0.7 so we get T = 250 + 840 = 1090 N Now force is F = T + 500 + 1600*0.7 = 1090 + 500 + 1120 = 2710 N
 one year ago
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