Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2.
Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck.
I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

- schrodinger

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

Given the forces of friction, the masses and acceleration, you can use F = ma.

- anonymous

your a fluttering dumbass -.-

- anonymous

F - T - 500 = 1600 * 0.70
F + T -250 = 1200 * 0.70
|dw:1364442269773:dw|
Work out what T and F are.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Lol thats the whole point. I don't know how.. i drew the diagram like that just dont know where to go from there.

- anonymous

If you managed to draw the diagram, the rest is easy. You need to apply F = ma to each object. All horizontal forces on the truck are F, T and friction. Just be careful about the direction.

- anonymous

for the truck - F is the force forwards, T(tension) - imagine this as a rope between truck and trailor. So for truck, the rope (T) is pulling the truck backwards. and friction(opposite to truck's motion) pulling the truck backwards.
So we have F - T - frictionofTruck = mass of truck * acceleration of truck
F - T - 500 = 1600 * 0.7
Now for the trailor, the trailor is moving because of the pull from the rope (T), and the friction is opposing its motion .
So, T - frictionOnTrailor = mass of trailor * acceleration
Hence
T - 250 = 1200 * 0.7
so we get T = 250 + 840 = 1090 N
Now force is F = T + 500 + 1600*0.7 = 1090 + 500 + 1120 = 2710 N

Looking for something else?

Not the answer you are looking for? Search for more explanations.