A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2.
Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck.
I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?
anonymous
 3 years ago
Large truck with massof 1600kg pulling a trailer with mass of 1200kg. Both accelerate at 0.70m/s^2. Determine the tension force between the truck and trailer and the force with which the truck is pulling if the force of friction is 250 N for the trailer and 500 N for the truck. I dont get how to solve for tension at all, I really need help. Please tell me how to solve for tension simply?

This Question is Open

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Given the forces of friction, the masses and acceleration, you can use F = ma.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your a fluttering dumbass .

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0F  T  500 = 1600 * 0.70 F + T 250 = 1200 * 0.70 dw:1364442269773:dw Work out what T and F are.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Lol thats the whole point. I don't know how.. i drew the diagram like that just dont know where to go from there.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0If you managed to draw the diagram, the rest is easy. You need to apply F = ma to each object. All horizontal forces on the truck are F, T and friction. Just be careful about the direction.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0for the truck  F is the force forwards, T(tension)  imagine this as a rope between truck and trailor. So for truck, the rope (T) is pulling the truck backwards. and friction(opposite to truck's motion) pulling the truck backwards. So we have F  T  frictionofTruck = mass of truck * acceleration of truck F  T  500 = 1600 * 0.7 Now for the trailor, the trailor is moving because of the pull from the rope (T), and the friction is opposing its motion . So, T  frictionOnTrailor = mass of trailor * acceleration Hence T  250 = 1200 * 0.7 so we get T = 250 + 840 = 1090 N Now force is F = T + 500 + 1600*0.7 = 1090 + 500 + 1120 = 2710 N
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.