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anonymous
 3 years ago
geometry help
anonymous
 3 years ago
geometry help

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nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1add the area of the rectangle to the area of the right triangle \[(l \times w)+(\frac{ 1 }{ 2 }bh)\]

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1@johndenison it is a disservice to this website to be giving out answers.

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1@ParthKohli @AravindG

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0@johndenison thats right .You are NOT allowed to give away answers according to our code of conduct .Refer http://openstudy.com/codeofconduct . Instead help the asker get to the solution by being a guide along the answering process . WELCOME TO OPENSTUDY ! :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0all i wanted was help to start it out.

AravindG
 3 years ago
Best ResponseYou've already chosen the best response.0did you get the help @vivianrush ?Any doubts?

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364443833368:dw

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1the proper equation to find the height of the triangle will have to be: x+8 = 13 you can begin with this. The illustration is there to guide you how to begin. As I have stated earlier, you can find the area of the diagram by adding the area of the triangle and the area of the rectangle. you were given a rectangle with both the length and width dimensions, but you were given a triangle with only one dimension (just the base but without the height. Area of RECTANGLE = length * width Area of TRIANGLE = 1/2 (base * height)

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364444683090:dw

nincompoop
 3 years ago
Best ResponseYou've already chosen the best response.1\[A=(l \times w) + \frac{ 1 }{ 2 } (b \times h)\] \[l = 13; w = 9; b =11; h= (l8)\] we're going to need more than being an spectator when it comes to solving math problems @vivianrush
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