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hlpwntdBest ResponseYou've already chosen the best response.0
regression estimate = 15 the intervals in standard units are: 1.2815 < 80% > 1.2815 1.96 < 95% > 1.96 regression estimate/rms error = 1.2815 score/rms error = 1.96
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
not 24.7 here is a tip: score = regression estimate (score/rms error) / (regression estimate/rms error)
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
If the scatter diagram is footballshaped, the r.m.s. error for the regression line can be used like a standard deviation for the regression line. 15 points correspond to a zscore of 1.2815. Therefore one standard deviation is 15/1.2815 = 11.7 points. About 95% of the points are within two r.m.s.errors from the regression line. For about 95% of the students, the regression estimate of final score based on midterm score is correct to within 2 * 11.7 = 23.4 points.
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
kropot72, where do you get the 2 from in your 2 * 11.7 = 23.4 ?
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
You could use 1.96 instead of 2. About 95% of the points are within 1.96 r.m.s.errors from the regression line.
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
score = 15*1.96/1.2815 = 22.94
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
For about 95% of the students, the regression estimate of final score based on midterm score is correct to within 23 points. Note that the question says " For about 95% of the students .......". Therefore an approximate rounded off answer is expected, in my opinion.
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
a rounded answer would be 23, otherwise you would have to round all the other factors and denominators and it won't give u an accurate rounded answer an exact answer is the most approximatively correct answer :D
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
So are you in doubt as to the value to put for the answer?
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
nope id put 22.94 without a doubt an accurate answer is always the right 1, even with approximations. you can always round your answer if it is specifically required  just my opinion
 one year ago

kropot72Best ResponseYou've already chosen the best response.0
Not a problem with that. However the question itself is not precise when it states "For about 80% of the students ......" and "For about 95% of the students ......"
 one year ago

hlpwntdBest ResponseYou've already chosen the best response.0
imo 23.4 wouldn't work because rounding only 1 factor is wrong. here is why:  if you come with the right formula and your teacher can see that you came with the right 1 and rounded 1 factor on purpose, the answer would be correct, but it might be subject to your teacher's interpretation rather than vs your answer's raw accuracy  if you give an answer and the question doesn't require that you write the formula, the teacher has no way to accurately understand that you rounded 1 factor. your teacher's interpretation could be that you are wrong, even if your answer is actually right do i make sense ? :D
 one year ago

panduBest ResponseYou've already chosen the best response.0
PROBLEM 2 Weights of male mountain lions follow the normal distribution with a median of 150 lb and an interquartile range of 8.2 lb. 2A : 2.0 POINTS Find the 75th percentile of the weights.
 one year ago
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