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electrokid
 one year ago
Best ResponseYou've already chosen the best response.3what does that "*" represent?

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0* is equal to \(\times \)

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0no.., it just times

niksva
 one year ago
Best ResponseYou've already chosen the best response.0@gerryliyana solve for RHS first by using the values of dimensional vectors given in question

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3\[\vec{a}\times\vec{b}=\left\begin{matrix} \hat{x}&\hat{y}&\hat{z}\\ u&v&0\\ x&y&0 \end{matrix}\right =\hat{z}(uyvx)\\ \vec{a}\cdot\vec{b}=ux+vy\\ ab = (u+iv)(x+iy)=ux+i(vx)+i(uy)+(i^2)(xy) \]

myko
 one year ago
Best ResponseYou've already chosen the best response.0are you sure it's right? Because: a.b=ux+vy iz(axb)=i(uyxv) and a*b=uxvy+i(uy+vx) so it is not equal: uxvy+i(uy+vx) =/= ux+vy+i(uyxv)

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3\[ab=(uyvx)+i(vx+uy)\]

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0its same with my answer @myko

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3\[ab=\hat{z}\cdot(\vec{a}\times\vec{b})+i(\vec{a}\cdot\vec{b})\]

myko
 one year ago
Best ResponseYou've already chosen the best response.0vx+uy =/= a.b @electrokid

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0so what the right answer??

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3that "*" in the question must be a complex conjugate

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3then it seems you might have it right.

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0good idea!! oh my bad...,

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0yeah,"*" means conjugate

electrokid
 one year ago
Best ResponseYou've already chosen the best response.3always make sure that people are talking the same math language

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0thank you @electrokid

niksva
 one year ago
Best ResponseYou've already chosen the best response.0@electrokid if "*" is complex conjugate then it will be rightly solved

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0i got it now.., thank you guys :)

gerryliyana
 one year ago
Best ResponseYou've already chosen the best response.0by the way.., if all of you have a facebook., add me on facebook http://www.facebook.com/gerry.resmiliyana thank you so much!
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