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COMPLEX VARIABLE

Differential Equations
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what does that "*" represent?
* is equal to \(\times \)

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Other answers:

a cross-product?
no.., it just times
@gerryliyana solve for RHS first by using the values of dimensional vectors given in question
\[\vec{a}\times\vec{b}=\left|\begin{matrix} \hat{x}&\hat{y}&\hat{z}\\ u&v&0\\ x&y&0 \end{matrix}\right| =\hat{z}(uy-vx)\\ \vec{a}\cdot\vec{b}=ux+vy\\ ab = (u+iv)(x+iy)=ux+i(vx)+i(uy)+(i^2)(xy) \]
are you sure it's right? Because: a.b=ux+vy iz(axb)=i(uy-xv) and a*b=ux-vy+i(uy+vx) so it is not equal: ux-vy+i(uy+vx) =/= ux+vy+i(uy-xv)
\[ab=(uy-vx)+i(vx+uy)\]
its same with my answer @myko
yeah i think so
\[ab=\hat{z}\cdot(\vec{a}\times\vec{b})+i(\vec{a}\cdot\vec{b})\]
vx+uy =/= a.b @electrokid
so what the right answer??
oh yea.. my bad..
that "*" in the question must be a complex conjugate
then it seems you might have it right.
good idea!! oh my bad...,
yeah,"*" means conjugate
always make sure that people are talking the same math language
thank you @electrokid
@electrokid if "*" is complex conjugate then it will be rightly solved
i got it now.., thank you guys :)
by the way.., if all of you have a facebook., add me on facebook http://www.facebook.com/gerry.resmiliyana thank you so much!

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