## ParthKohli Group Title What are the roots of $$y = x^2$$? one year ago one year ago

1. goformit100 Group Title

|dw:1364477055858:dw||dw:1364477070806:dw|

2. ParthKohli Group Title

A friend of mine suggests that people don't think that zero is a real solution.

3. Mertsj Group Title

The roots are the x intercepts. Set y to 0 and you will see that x=0 is a double root which indicates a point of tangency to the x axis at x = 0

4. Mertsj Group Title

People can think whatever they want. Doesn't make it true.

5. ParthKohli Group Title

$x^2 = 0 \implies x = 0$

6. goformit100 Group Title

You friend is a crazy guy.

7. ParthKohli Group Title

OK, thank you!

8. Mertsj Group Title

|dw:1364476304306:dw|

9. Mertsj Group Title

yw

10. ParthKohli Group Title

Thanks, enough to explain.

11. UnkleRhaukus Group Title

$y=x^2$$x^2-y=0$$x_{1,2}=\frac{0\pm\sqrt{0^2-4(1)(-y)}}{2(1)}\\=\frac{\pm\sqrt{4y}}{2}\\ =\pm \sqrt y$

12. ParthKohli Group Title

Nice solution, but by "roots", I meant zeroes :-)

13. UnkleRhaukus Group Title

$0=\pm\sqrt0$

14. ParthKohli Group Title

Ah, lol!