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What are the roots of \(y = x^2\)?

Mathematics
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A friend of mine suggests that people don't think that zero is a real solution.
The roots are the x intercepts. Set y to 0 and you will see that x=0 is a double root which indicates a point of tangency to the x axis at x = 0

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Other answers:

People can think whatever they want. Doesn't make it true.
\[x^2 = 0 \implies x = 0\]
You friend is a crazy guy.
OK, thank you!
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yw
Thanks, enough to explain.
\[y=x^2\]\[x^2-y=0\]\[x_{1,2}=\frac{0\pm\sqrt{0^2-4(1)(-y)}}{2(1)}\\=\frac{\pm\sqrt{4y}}{2}\\ =\pm \sqrt y\]
Nice solution, but by "roots", I meant zeroes :-)
\[0=\pm\sqrt0\]
Ah, lol!

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