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goformit100
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364477055858:dwdw:1364477070806:dw

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0A friend of mine suggests that people don't think that zero is a real solution.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2The roots are the x intercepts. Set y to 0 and you will see that x=0 is a double root which indicates a point of tangency to the x axis at x = 0

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.2People can think whatever they want. Doesn't make it true.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2 = 0 \implies x = 0\]

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0You friend is a crazy guy.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Thanks, enough to explain.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0\[y=x^2\]\[x^2y=0\]\[x_{1,2}=\frac{0\pm\sqrt{0^24(1)(y)}}{2(1)}\\=\frac{\pm\sqrt{4y}}{2}\\ =\pm \sqrt y\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Nice solution, but by "roots", I meant zeroes :)
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