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goformit100 Group TitleBest ResponseYou've already chosen the best response.0
dw:1364477055858:dwdw:1364477070806:dw
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
A friend of mine suggests that people don't think that zero is a real solution.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
The roots are the x intercepts. Set y to 0 and you will see that x=0 is a double root which indicates a point of tangency to the x axis at x = 0
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
People can think whatever they want. Doesn't make it true.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
\[x^2 = 0 \implies x = 0\]
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
You friend is a crazy guy.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
OK, thank you!
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.2
dw:1364476304306:dw
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Thanks, enough to explain.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[y=x^2\]\[x^2y=0\]\[x_{1,2}=\frac{0\pm\sqrt{0^24(1)(y)}}{2(1)}\\=\frac{\pm\sqrt{4y}}{2}\\ =\pm \sqrt y\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Nice solution, but by "roots", I meant zeroes :)
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.0
\[0=\pm\sqrt0\]
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Ah, lol!
 one year ago
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