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goformit100Best ResponseYou've already chosen the best response.0
dw:1364477055858:dwdw:1364477070806:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
A friend of mine suggests that people don't think that zero is a real solution.
 one year ago

MertsjBest ResponseYou've already chosen the best response.2
The roots are the x intercepts. Set y to 0 and you will see that x=0 is a double root which indicates a point of tangency to the x axis at x = 0
 one year ago

MertsjBest ResponseYou've already chosen the best response.2
People can think whatever they want. Doesn't make it true.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
\[x^2 = 0 \implies x = 0\]
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
You friend is a crazy guy.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Thanks, enough to explain.
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.0
\[y=x^2\]\[x^2y=0\]\[x_{1,2}=\frac{0\pm\sqrt{0^24(1)(y)}}{2(1)}\\=\frac{\pm\sqrt{4y}}{2}\\ =\pm \sqrt y\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
Nice solution, but by "roots", I meant zeroes :)
 one year ago
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