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DLS
Group Title
1)A disc has pure rotation.It has angular velocity w.It then comes into contact with a surface which has static friction us,kinetic friction uk and rolling friction ur,When will the disc stop?
2)A disc is placed on the ground.The coefficient of friction is u,and the coefficient of rolling friction is u_r.What is the minimum force required to move the disc?The force is applied at the bottom most point
 one year ago
 one year ago
DLS Group Title
1)A disc has pure rotation.It has angular velocity w.It then comes into contact with a surface which has static friction us,kinetic friction uk and rolling friction ur,When will the disc stop? 2)A disc is placed on the ground.The coefficient of friction is u,and the coefficient of rolling friction is u_r.What is the minimum force required to move the disc?The force is applied at the bottom most point
 one year ago
 one year ago

This Question is Closed

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
@Mashy @shubhamsrg
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
@yrelhan4 @RnR :P
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
should we consider all the types of friction in question 1? :P.. we can only consider rotational rigth? :D..
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
you will require all 3,when you start the question you will realise :)
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
but at a time only one friction comes into play.. ! :/
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
yes..start with static one
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
but it ll only act for a particular small amount of time.. which i dunno how we could calculate :P
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
and besides i really don't think the static and kinetic have to be considered.. i mean how can you consider static? the wheel is already in rotation .. so no question of static.. and the moment it would come in contact it would start rolling OR slipping.. so only one would come into picture!
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
proceed with whatever u want :/
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
wait.. rolling friction wouldn't make it stop :D.. it should be the kinetic friction :D
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
arrre kar to :/
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
so as i was saying it should be rotational friction itself anyways wat about mass and the radius?!
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
lol just like tat you grant wishes huh? :D lol
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
assume anything duh
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
so now there would be a force acting creating a torque that would eventually sue the rolling.. so i guess all you have to do is finde the torque.. then you can find the deceleration!
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
in the end you will get F=f
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
after applying torque equation n stuff
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
what?!? f = (mur)N/R.... thats the formula for rolling friction right?!
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
/R? upon R?no simply u(r)N
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
it depends upon the dimensions of mur .. rolling friction can be expressed in both the ways :P
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
abe yr ata hai to kar kya ghante me reply kar rha h :/
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
^ Best response. :P
 one year ago

Mashy Group TitleBest ResponseYou've already chosen the best response.0
arre sorry.. i was wtching dbz abridged :D..
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Can you draw a picture?
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
When it comes to static and kinetic friction, my intuition, and it could be wrong, is that static friction is only meant as a thresh hold to find out whether the object will be moved. Kinetic friction on the other hand is something which applied a resting force over time.
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
What is your definition of µr (rolling friction coefficient)? It is important, because it is only if rolling friction exists that the disc will eventually come to a halt. Otherwise, it will roll for ever.
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.1
Your answer is right. I don't have the exact definition of µr (rolling friction coefficient) or even rolling friction. I just know that rolling friction is 1/100th of sliding friction and it depends on hardness of surface. Sorry,ill be glad to get some details about it!
 one year ago

VincentLyon.Fr Group TitleBest ResponseYou've already chosen the best response.0
The first phase of the motion is sliding. It is not so straightforward to find the time it will last. The answer is \(\tau_1=\Large \frac {R\omega_0}{3\mu _kg}\) The remaining rotation velocity is \(\omega_1=\Large \frac {\omega_0}{3}\) Velocity of centre of mass is \(v_1=\Large \frac {R\omega_0}{3}\)
 one year ago
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