A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Find all critical numbers by hand. If available, use graphing technology to determine whether the critical number represents a local maximum, local minimum, or neither.
f(x) = x^4  3x^3 + 2
 one year ago
Find all critical numbers by hand. If available, use graphing technology to determine whether the critical number represents a local maximum, local minimum, or neither. f(x) = x^4  3x^3 + 2

This Question is Closed

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@rajathsbhat can u help?

rajathsbhat
 one year ago
Best ResponseYou've already chosen the best response.0not too sure about this :\

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0@electrokid can u help?

tomatooooo
 one year ago
Best ResponseYou've already chosen the best response.0are you allowed to use calculus for this? or algebra 2?

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0okay the derivative is x^2(4x  9)

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1set that equal to 0 and solve for x

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.1that's your criticle number

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0how do i determine whether it is local maximum, minimum or either

modphysnoob
 one year ago
Best ResponseYou've already chosen the best response.11)Plug in Crit point into F''(t); positive number mean min, negative number mean max
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.