• anonymous
1. Let g be the function given by g(x)=integrate from -4 to x f(t)dt. For each of g(-1), g'(-1), and g''(-1), find the value of state that it does not exist. 2. For the function g defined in part 1., find the x-coordinate of each point of inflection of the graph of g on the open interval -4
  • Stacey Warren - Expert
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  • katieb
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  • anonymous
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  • anonymous
step 1) from graph, f(x) is a piecewise linear function. and hence, g(x) is piecewise quadratic step 2) g(x) is quadratic and continuous derivative exists step 3) g'(x) will be piecewise linear and continuous step 4) g''(x) will be constant terms in each interval and discontinuous at the change of domains. hence, g''(-1) cannot exist.
  • goformit100
As its a critical graph the reading are very difficult to be talkne out.

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