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Selena2345
 2 years ago
Ms.Hobson agrees to pay 11% interest on a loan for her new automobile. She is charged $2200 interest on a loan for 1 year. How much did she borrow ?
Selena2345
 2 years ago
Ms.Hobson agrees to pay 11% interest on a loan for her new automobile. She is charged $2200 interest on a loan for 1 year. How much did she borrow ?

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ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1She is charged $2200 interest on a loan for 1 year Let she borrowed x , then interest to be paid in a year \[I=x\times 11\%\] interest is 2200 \[2200=x\times \frac{11}{100}\] Can you find x?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1First step: Multiply both sides by 100, what would you get?

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1\[2200\times 100=x\times \frac{11}{100}\times 100\]

Selena2345
 2 years ago
Best ResponseYou've already chosen the best response.12200 x 100=220000 11/100 x 11=11

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1\[220000=x\times 11\] Now divide both sides by 11 to find x

Selena2345
 2 years ago
Best ResponseYou've already chosen the best response.1220000/11=20000 11/11=1

ash2326
 2 years ago
Best ResponseYou've already chosen the best response.1Correct, this is the amount borrowed. Do you understand?
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