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Ms.Hobson agrees to pay 11% interest on a loan for her new automobile. She is charged $2200 interest on a loan for 1 year. How much did she borrow ?
 one year ago
 one year ago
Ms.Hobson agrees to pay 11% interest on a loan for her new automobile. She is charged $2200 interest on a loan for 1 year. How much did she borrow ?
 one year ago
 one year ago

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ash2326Best ResponseYou've already chosen the best response.1
She is charged $2200 interest on a loan for 1 year Let she borrowed x , then interest to be paid in a year \[I=x\times 11\%\] interest is 2200 \[2200=x\times \frac{11}{100}\] Can you find x?
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
First step: Multiply both sides by 100, what would you get?
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
\[2200\times 100=x\times \frac{11}{100}\times 100\]
 one year ago

Selena2345Best ResponseYou've already chosen the best response.1
2200 x 100=220000 11/100 x 11=11
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
\[220000=x\times 11\] Now divide both sides by 11 to find x
 one year ago

Selena2345Best ResponseYou've already chosen the best response.1
220000/11=20000 11/11=1
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
so what you got for x?
 one year ago

ash2326Best ResponseYou've already chosen the best response.1
Correct, this is the amount borrowed. Do you understand?
 one year ago
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