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anonymous
 3 years ago
work done to move a capacitor in parrallel a distance x
anonymous
 3 years ago
work done to move a capacitor in parrallel a distance x

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364587708013:dw

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.0I was just tagging myself.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0herre i mean to move it away from the other by applying a force \[F_A\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0work done = change in internal energy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01) Energy in a capacitor \(U={1\over2}{Q^2\over C}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.02) what changes when you separate the plates? capacitance: \[C={\epsilon_0kA\over d}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, \[U={1\over2}{Q^2d\over\epsilon_0kA}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0W = final energy  initial energy

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0remember that Q does not change in this case, but C and V do

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Jonask you are increasing the separation between the plates, right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes i was hoping for \[dW=Fdx\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i dont see x in you expressions above

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0https://www.edx.org/courses/MITx/8.02x/2013_Spring/courseware/Week_3/sequence_3_1/

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i would like us to do it intergration way

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0https://www.youtube.com/watch?feature=player_embedded&v=bV0zosBkKC0#at=116

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you do not necessarily have to use the integration way. total work done is independent of path followed; depends on the initial and final states only!
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