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Jonask Group Title

work done to move a capacitor in parrallel a distance x

  • one year ago
  • one year ago

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  1. yrelhan4 Group Title
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    *

    • one year ago
  2. Jonask Group Title
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    |dw:1364587708013:dw|

    • one year ago
  3. yrelhan4 Group Title
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    I was just tagging myself.

    • one year ago
  4. Jonask Group Title
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    herre i mean to move it away from the other by applying a force \[F_A\]

    • one year ago
  5. Jonask Group Title
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    *

    • one year ago
  6. electrokid Group Title
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    work done = change in internal energy

    • one year ago
  7. electrokid Group Title
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    1) Energy in a capacitor \(U={1\over2}{Q^2\over C}\)

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  8. Jonask Group Title
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    F=qE

    • one year ago
  9. electrokid Group Title
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    2) what changes when you separate the plates? capacitance: \[C={\epsilon_0kA\over d}\]

    • one year ago
  10. electrokid Group Title
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    so, \[U={1\over2}{Q^2d\over\epsilon_0kA}\]

    • one year ago
  11. electrokid Group Title
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    W = final energy - initial energy

    • one year ago
  12. electrokid Group Title
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    remember that Q does not change in this case, but C and V do

    • one year ago
  13. electrokid Group Title
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    @Jonask you are increasing the separation between the plates, right?

    • one year ago
  14. Jonask Group Title
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    yes i was hoping for \[dW=Fdx\]

    • one year ago
  15. Jonask Group Title
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    i dont see x in you expressions above

    • one year ago
  16. Jonask Group Title
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    https://www.edx.org/courses/MITx/8.02x/2013_Spring/courseware/Week_3/sequence_3_1/

    • one year ago
  17. Jonask Group Title
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    i would like us to do it intergration way

    • one year ago
  18. Jonask Group Title
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    https://www.youtube.com/watch?feature=player_embedded&v=bV0zosBkKC0#at=116

    • one year ago
  19. electrokid Group Title
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    you do not necessarily have to use the integration way. total work done is independent of path followed; depends on the initial and final states only!

    • one year ago
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