Jonask Group Title work done to move a capacitor in parrallel a distance x one year ago one year ago

1. yrelhan4 Group Title

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3. yrelhan4 Group Title

I was just tagging myself.

herre i mean to move it away from the other by applying a force $F_A$

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6. electrokid Group Title

work done = change in internal energy

7. electrokid Group Title

1) Energy in a capacitor $$U={1\over2}{Q^2\over C}$$

F=qE

9. electrokid Group Title

2) what changes when you separate the plates? capacitance: $C={\epsilon_0kA\over d}$

10. electrokid Group Title

so, $U={1\over2}{Q^2d\over\epsilon_0kA}$

11. electrokid Group Title

W = final energy - initial energy

12. electrokid Group Title

remember that Q does not change in this case, but C and V do

13. electrokid Group Title

@Jonask you are increasing the separation between the plates, right?

yes i was hoping for $dW=Fdx$

i dont see x in you expressions above