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anonymous
 3 years ago
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.
anonymous
 3 years ago
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1364660898982:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0using this equation i got moles = 0.020194 moles

.Sam.
 3 years ago
Best ResponseYou've already chosen the best response.0We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but what I need is how to get the molecular formula because I only have percent by mass

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS
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