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 one year ago
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.
 one year ago
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

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znimon
 one year ago
Best ResponseYou've already chosen the best response.1At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?

znimon
 one year ago
Best ResponseYou've already chosen the best response.1Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law

goformit100
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364660898982:dw

znimon
 one year ago
Best ResponseYou've already chosen the best response.1using this equation i got moles = 0.020194 moles

.Sam.
 one year ago
Best ResponseYou've already chosen the best response.0We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas

znimon
 one year ago
Best ResponseYou've already chosen the best response.1but what I need is how to get the molecular formula because I only have percent by mass

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS

Yahoo!
 one year ago
Best ResponseYou've already chosen the best response.0Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS
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