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znimon

Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

  • one year ago
  • one year ago

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  1. znimon
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    At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?

    • one year ago
  2. znimon
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    Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law

    • one year ago
  3. goformit100
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    |dw:1364660898982:dw|

    • one year ago
  4. znimon
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    using this equation i got moles = 0.020194 moles

    • one year ago
  5. znimon
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    @Callisto

    • one year ago
  6. znimon
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    @Yahoo!

    • one year ago
  7. znimon
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    @.Sam.

    • one year ago
  8. znimon
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    CN or C2N2......?

    • one year ago
  9. znimon
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    any ideas?

    • one year ago
  10. .Sam.
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    yes

    • one year ago
  11. .Sam.
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    We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas

    • one year ago
  12. .Sam.
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    • one year ago
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  13. znimon
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    yes I got that

    • one year ago
  14. znimon
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    but what I need is how to get the molecular formula because I only have percent by mass

    • one year ago
  15. znimon
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    so I dont know

    • one year ago
  16. Yahoo!
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    n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS

    • one year ago
  17. Yahoo!
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    Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS

    • one year ago
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