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Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

Chemistry
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At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?
Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law
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using this equation i got moles = 0.020194 moles
@.Sam.
CN or C2N2......?
any ideas?
yes
We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas
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yes I got that
but what I need is how to get the molecular formula because I only have percent by mass
so I dont know
n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS
Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS

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