anonymous
  • anonymous
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.
Chemistry
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?
anonymous
  • anonymous
Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law
goformit100
  • goformit100
|dw:1364660898982:dw|

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anonymous
  • anonymous
using this equation i got moles = 0.020194 moles
anonymous
  • anonymous
@Callisto
anonymous
  • anonymous
@Yahoo!
anonymous
  • anonymous
@.Sam.
anonymous
  • anonymous
CN or C2N2......?
anonymous
  • anonymous
any ideas?
.Sam.
  • .Sam.
yes
.Sam.
  • .Sam.
We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas
.Sam.
  • .Sam.
1 Attachment
anonymous
  • anonymous
yes I got that
anonymous
  • anonymous
but what I need is how to get the molecular formula because I only have percent by mass
anonymous
  • anonymous
so I dont know
anonymous
  • anonymous
n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS
anonymous
  • anonymous
Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS

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