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znimon
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Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.
 one year ago
 one year ago
znimon Group Title
Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.
 one year ago
 one year ago

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znimon Group TitleBest ResponseYou've already chosen the best response.1
At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.1
dw:1364660898982:dw
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
using this equation i got moles = 0.020194 moles
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
CN or C2N2......?
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
yes I got that
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
but what I need is how to get the molecular formula because I only have percent by mass
 one year ago

znimon Group TitleBest ResponseYou've already chosen the best response.1
so I dont know
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS
 one year ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS
 one year ago
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