## znimon 2 years ago Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen.

1. znimon

At 25oC and 751 torr, 1.05 g of the gas occupies 0.500 L. What is the molecular formula for the gas?

2. znimon

Does it matter if this is an ideal gass because I would like to use PV = nRT = ideal gass law

3. goformit100

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4. znimon

using this equation i got moles = 0.020194 moles

5. znimon

@Callisto

6. znimon

@Yahoo!

7. znimon

@.Sam.

8. znimon

CN or C2N2......?

9. znimon

any ideas?

10. .Sam.

yes

11. .Sam.

We can get the number of moles of the total gas with PV=nRT, see picture below, we get 0.020195 mol of gas

12. .Sam.

13. znimon

yes I got that

14. znimon

but what I need is how to get the molecular formula because I only have percent by mass

15. znimon

so I dont know

16. Yahoo!

n= m/M PV = nRT PV = m/M R T From this equation find M ie MOLECULAR MASS

17. Yahoo!

Form this info ::::: Analysis of a gas indicated that 46.2 % of its mass was carbon and 53.8% of the mass was nitrogen. find Emperical Formula n = MOLECULAR MASS / EMPERICAL FORMULA MASS