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A plane is defined by the equation: x=4y+2z=16.
Find two vectors parallel to the plane.
 one year ago
 one year ago
A plane is defined by the equation: x=4y+2z=16. Find two vectors parallel to the plane.
 one year ago
 one year ago

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SerikMBBest ResponseYou've already chosen the best response.0
do you know the rule of parallelism?
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
Two vectors and are parallel if their cross product is zero, i.e., .u*v=0
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
Okay do what do i do :S @SerikMB
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
do you have exact answers?
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
one of them may probable be y=1/2x+2z
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
Like what do i do to come up with that answer ?
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
when two equations are parallel they have the same slopes
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
as it says parallel the equation is linear so it's form is y=kx+b , but here instead of k it will be the slope
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
then as vectors usually start at (0,0) point
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
you can substitue it into the formula \[Y_{1}Y _{2}=m(X _{1}X _{2})\]
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
given this equation: x=4y+2z=16.
 one year ago

SerikMBBest ResponseYou've already chosen the best response.0
yea it's just 3 dimensional
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
im still not understanding this
 one year ago
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