anonymous
  • anonymous
to avoid a negative square root, how can i use the square root property on this ? (x+81)^2 = -158 or am i missing something about the rules of negative numbers and square roots ? I thought negative square roots were not allowed. thanks :)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
tkhunny
  • tkhunny
If we allow only Real Numbers, we stop in our tracks and say, "No Solution".
anonymous
  • anonymous
in math if it is a negative number we call it the number I because it is imaginary which is why we write something like this sqrt -158i if not allowed than no solution..
anonymous
  • anonymous
Negative numbers result in imaginary numbers. Imaginary numbers scare me.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it is nothing to be scared of
anonymous
  • anonymous
the answer to the original equation (generated at math.com) is x= 11 and x=7. the original equation is : x^2 -18x +77 =0 my attempt at the quadratic formula produced : x=(18 ± 2√(61) / 2) i decided i had done something incorrectly and started completing the square from the original equation. can adding 158 to both sides be done while completing the square ? what happened to the reply about adding 158 ?
anonymous
  • anonymous
okay I know what is wrong
anonymous
  • anonymous
have you tried this A^2+B^2+C^2 this is the other form of qurad.
anonymous
  • anonymous
it should be =C^2 not plus srry..
anonymous
  • anonymous
trying it now.
anonymous
  • anonymous
what you get for answer?
anonymous
  • anonymous
1585=5929 i thought that formula looked familiar, so i searched for it and found he "Pythagorean theorem" http://en.wikipedia.org/wiki/Pythagorean_theorem perhaps, i have misunderstood something.
anonymous
  • anonymous
@gemstonegirl come and see this
anonymous
  • anonymous
need to know something does the problem state that no negative numbers can be the answer?
anonymous
  • anonymous
ok, before the beginning of march, most of algebra was unknown to me. i only had the basic concept of replacing numbers with variables and solving for unknowns. this was required for calculations in ohms law when i was in collage. P=I*E for example. there was nothing complected about it , yet i struggled due to my lack of mathematical knowledge. i used an advanced TI calculator to solve what i did not comprehend. i dropped out of collage (foolish) because it all seemed overwhelming and i moved out of state with a girl that turned out to be insane. that was 5~ ago. when i came back , i found collage debt and a new opportunity with an apprenticeship program by IBEW (international brotherhood of electrical workers). there is an aptitude test near the end of April that involves algebra. i have been cramming my head with algebra ever since the day i learned of this. so, do not fret over your lack of algebra knowledge or mistakes, because i have less ten two months of algebra study ;)
anonymous
  • anonymous
@ibew try this http://math.about.com/od/Equations/ss/Quadratic
anonymous
  • anonymous
@ibew I amm studing math myself and this Summer I start on-line at IU East so math is my life and mistakes like this I should not make..
anonymous
  • anonymous
@ibew there is no answer for this problem. also use the sqrt to see there is no answer to this problem ...
anonymous
  • anonymous
is that allowed while "completing the square" ?
anonymous
  • anonymous
the original equation is : x^2 -18x +77 =0
anonymous
  • anonymous
i did: "ibew Medals 0 the answer to the original equation (generated at math.com) is x= 11 and x=7. the original equation is : x^2 -18x +77 =0 my attempt at the quadratic formula produced : x=(18 ± 2√(61) / 2) i decided i had done something incorrectly and started completing the square from the original equation. can adding 158 to both sides be done while completing the square ? what happened to the reply about adding 158 ? an hour ago" "
anonymous
  • anonymous
:)
anonymous
  • anonymous
@ibew there is no answer..
anonymous
  • anonymous
this web site says there is an answer. http://www.algebrahelp.com/calculators/equation/calc.do;jsessionid=52F7E4DBE8C8F1538B2EE5187783E04C?equation=x^2+-18x+%2B77+%3D0+&solvf=AUTO i am looking it over now. i also added your link to my "math" book marks folder, thanks :)
anonymous
  • anonymous
Your welcome anytime
anonymous
  • anonymous
it does not use the quadratic formula or "completing the square" . i am nor well versed on factoring polynomials . i have memorizing the quadratic formula and completing the square because they achieve results 100% of the various problems.
anonymous
  • anonymous
if any one can show me what i am doing wrong or how to get beyond this "soon to be" negative square root", it would be greatly appreciated. :)
anonymous
  • anonymous
if any one has successfully solved the equation with the quadratic formula, that would help also.
anonymous
  • anonymous
i think the decision is unanimous that there is no solution to this :D ure online answers may have been wrong ...never know
anonymous
  • anonymous
@Luis_Rivera , thanks, i will post the question again with more information.
anonymous
  • anonymous
lol sorry i dont know that far ..but u will have to change up the equation ...

Looking for something else?

Not the answer you are looking for? Search for more explanations.