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DLS
 3 years ago
Domain of..sqrt{x152} ?
DLS
 3 years ago
Domain of..sqrt{x152} ?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \biggx15\bigg2 > 0 \]

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x152}\] better...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Add 2 to both sides. Where areyou getting stuck?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0I don't know how to deal with mod functions while solving for domain.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where is the mod though?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Huge \sqrt{x152}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so when you say 'mod' you mean the absolute value function?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ f(x) < a\implies a<f(x)<a\\ f(x) > a\implies a<f(x),\quad f(x)<a\\ \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[ \biggx15\bigg >2 \implies x15 < 2\quad\quad x15 >2 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0The equations will keep splitting up and you'll have to keep track of all of them.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0okay,ill try and let you know!

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0x1<3 x1<3 x1>7 x1>7 ?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0x1<3 x1>7 x1<3 x1>3 x1>7 x1<7

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1yup. thats right i guess.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0ill do after this :/ thanks~

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0looks like you messed up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is a really tedious problem man.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1hey wio. x1<3 x1>7 x1<3 x1>3 x1>7 x1<7 Thats right no?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so far, that is right.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Hugex15\bigg2 > 0\] >x<4 So lets take x as 3. Substituting, Okay positive. x>2 So lets take x as 1. Substituting, Okay positive. x>8 So lets take x as 9. Substituting, Okay positive. x<6 So lets take x as 7. Substituting, Okay positive. So that means all the solutions are acceptable.

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1So, x<4, x<6 > x<6 x>2, x>8 > x>8 right? @wio

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Looking at x<4 and x>2 is enough to tell you all solutions work.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0So drawing the wavy curve graph. dw:1364716700507:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you've got: \[ 2<x<4\\ x<6, \quad x>8 \]What happens at 5?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[\LARGE (\infty,5] U (8,\infty) \]

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0oh ye to tera answer agaya :P @yrelhan4 lol

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Combining these equations: \[ 2<x<4\\ x<6, \quad x>8 \]Makes me thing it's \(x\in (\infty,6)\cup (2,4)\cup (8,\infty)\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm, what are you using?

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0\[x\in (8,6)\cup (2,4)\cup (8,\infty)\] is the answer

yrelhan4
 3 years ago
Best ResponseYou've already chosen the best response.1Put 10 in the question.. Its >0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah, that answer doesn't make sense.

DLS
 3 years ago
Best ResponseYou've already chosen the best response.0i prefer @wio 's answer though,still we might be missing something maybe

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0There would have to be some other thing limiting the domain.
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