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wio
 one year ago
Best ResponseYou've already chosen the best response.1\[ \biggx15\bigg2 > 0 \]

mathslover
 one year ago
Best ResponseYou've already chosen the best response.1\[\sqrt{x152}\] better...

wio
 one year ago
Best ResponseYou've already chosen the best response.1Add 2 to both sides. Where areyou getting stuck?

DLS
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how to deal with mod functions while solving for domain.

DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\Huge \sqrt{x152}\]

wio
 one year ago
Best ResponseYou've already chosen the best response.1so when you say 'mod' you mean the absolute value function?

wio
 one year ago
Best ResponseYou've already chosen the best response.1\[ f(x) < a\implies a<f(x)<a\\ f(x) > a\implies a<f(x),\quad f(x)<a\\ \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1\[ \biggx15\bigg >2 \implies x15 < 2\quad\quad x15 >2 \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1The equations will keep splitting up and you'll have to keep track of all of them.

DLS
 one year ago
Best ResponseYou've already chosen the best response.0okay,ill try and let you know!

DLS
 one year ago
Best ResponseYou've already chosen the best response.0x1<3 x1<3 x1>7 x1>7 ?

DLS
 one year ago
Best ResponseYou've already chosen the best response.0x1<3 x1>7 x1<3 x1>3 x1>7 x1<7

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1yup. thats right i guess.

DLS
 one year ago
Best ResponseYou've already chosen the best response.0ill do after this :/ thanks~

wio
 one year ago
Best ResponseYou've already chosen the best response.1this is a really tedious problem man.

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1hey wio. x1<3 x1>7 x1<3 x1>3 x1>7 x1<7 Thats right no?

DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\Hugex15\bigg2 > 0\] >x<4 So lets take x as 3. Substituting, Okay positive. x>2 So lets take x as 1. Substituting, Okay positive. x>8 So lets take x as 9. Substituting, Okay positive. x<6 So lets take x as 7. Substituting, Okay positive. So that means all the solutions are acceptable.

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1So, x<4, x<6 > x<6 x>2, x>8 > x>8 right? @wio

wio
 one year ago
Best ResponseYou've already chosen the best response.1Looking at x<4 and x>2 is enough to tell you all solutions work.

DLS
 one year ago
Best ResponseYou've already chosen the best response.0So drawing the wavy curve graph. dw:1364716700507:dw

wio
 one year ago
Best ResponseYou've already chosen the best response.1you've got: \[ 2<x<4\\ x<6, \quad x>8 \]What happens at 5?

DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[\LARGE (\infty,5] U (8,\infty) \]

DLS
 one year ago
Best ResponseYou've already chosen the best response.0oh ye to tera answer agaya :P @yrelhan4 lol

wio
 one year ago
Best ResponseYou've already chosen the best response.1Combining these equations: \[ 2<x<4\\ x<6, \quad x>8 \]Makes me thing it's \(x\in (\infty,6)\cup (2,4)\cup (8,\infty)\)

DLS
 one year ago
Best ResponseYou've already chosen the best response.0\[x\in (8,6)\cup (2,4)\cup (8,\infty)\] is the answer

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.1Put 10 in the question.. Its >0

wio
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, that answer doesn't make sense.

DLS
 one year ago
Best ResponseYou've already chosen the best response.0i prefer @wio 's answer though,still we might be missing something maybe

wio
 one year ago
Best ResponseYou've already chosen the best response.1There would have to be some other thing limiting the domain.
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