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wioBest ResponseYou've already chosen the best response.1
\[ \biggx15\bigg2 > 0 \]
 one year ago

mathsloverBest ResponseYou've already chosen the best response.1
\[\sqrt{x152}\] better...
 one year ago

wioBest ResponseYou've already chosen the best response.1
Add 2 to both sides. Where areyou getting stuck?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
I don't know how to deal with mod functions while solving for domain.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\Huge \sqrt{x152}\]
 one year ago

wioBest ResponseYou've already chosen the best response.1
so when you say 'mod' you mean the absolute value function?
 one year ago

wioBest ResponseYou've already chosen the best response.1
\[ f(x) < a\implies a<f(x)<a\\ f(x) > a\implies a<f(x),\quad f(x)<a\\ \]
 one year ago

wioBest ResponseYou've already chosen the best response.1
\[ \biggx15\bigg >2 \implies x15 < 2\quad\quad x15 >2 \]
 one year ago

wioBest ResponseYou've already chosen the best response.1
The equations will keep splitting up and you'll have to keep track of all of them.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
okay,ill try and let you know!
 one year ago

DLSBest ResponseYou've already chosen the best response.0
x1<3 x1<3 x1>7 x1>7 ?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
x1<3 x1>7 x1<3 x1>3 x1>7 x1<7
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
yup. thats right i guess.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
ill do after this :/ thanks~
 one year ago

wioBest ResponseYou've already chosen the best response.1
this is a really tedious problem man.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
hey wio. x1<3 x1>7 x1<3 x1>3 x1>7 x1<7 Thats right no?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\Hugex15\bigg2 > 0\] >x<4 So lets take x as 3. Substituting, Okay positive. x>2 So lets take x as 1. Substituting, Okay positive. x>8 So lets take x as 9. Substituting, Okay positive. x<6 So lets take x as 7. Substituting, Okay positive. So that means all the solutions are acceptable.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
So, x<4, x<6 > x<6 x>2, x>8 > x>8 right? @wio
 one year ago

wioBest ResponseYou've already chosen the best response.1
Looking at x<4 and x>2 is enough to tell you all solutions work.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
So drawing the wavy curve graph. dw:1364716700507:dw
 one year ago

wioBest ResponseYou've already chosen the best response.1
you've got: \[ 2<x<4\\ x<6, \quad x>8 \]What happens at 5?
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[\LARGE (\infty,5] U (8,\infty) \]
 one year ago

DLSBest ResponseYou've already chosen the best response.0
oh ye to tera answer agaya :P @yrelhan4 lol
 one year ago

wioBest ResponseYou've already chosen the best response.1
Combining these equations: \[ 2<x<4\\ x<6, \quad x>8 \]Makes me thing it's \(x\in (\infty,6)\cup (2,4)\cup (8,\infty)\)
 one year ago

DLSBest ResponseYou've already chosen the best response.0
\[x\in (8,6)\cup (2,4)\cup (8,\infty)\] is the answer
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.1
Put 10 in the question.. Its >0
 one year ago

wioBest ResponseYou've already chosen the best response.1
Yeah, that answer doesn't make sense.
 one year ago

DLSBest ResponseYou've already chosen the best response.0
i prefer @wio 's answer though,still we might be missing something maybe
 one year ago

wioBest ResponseYou've already chosen the best response.1
There would have to be some other thing limiting the domain.
 one year ago
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