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joylee
I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C
@joylee first of all do you know what A' is?
|dw:1364714656096:dw|
A' will be U-A = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)
The shaded area above is A'
@naatiq is right. A' = 0 \(A' \cap C\) = \(0 \cap \{2,4,6,8,...\}\) |dw:1364714988770:dw| In the figure, we have two sets : first containing zero and other one containing \(\{2,4,6,8..\}\)
So it is clear that \(A'\cap C = \{0\} \cap \{2,4,6,8,...\}\) = \(\phi\) (empty set)
yes and thanks guys for your help I think I understand it now thanks again
You're welcome. \(\textbf{Welcome to OpenStudy}\)
I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here
Great to know, best of luck!