joylee Group Title I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C one year ago one year ago

1. mathslover Group Title

@joylee first of all do you know what A' is?

2. joylee Group Title

not really

3. mathslover Group Title

A' = U - A

4. mathslover Group Title

|dw:1364714656096:dw|

5. naatiq Group Title

A' will be U-A = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)

6. mathslover Group Title

The shaded area above is A'

7. mathslover Group Title

@naatiq is right. A' = 0 $$A' \cap C$$ = $$0 \cap \{2,4,6,8,...\}$$ |dw:1364714988770:dw| In the figure, we have two sets : first containing zero and other one containing $$\{2,4,6,8..\}$$

8. mathslover Group Title

So it is clear that $$A'\cap C = \{0\} \cap \{2,4,6,8,...\}$$ = $$\phi$$ (empty set)

9. mathslover Group Title

Got it @joylee ?

10. joylee Group Title

yes and thanks guys for your help I think I understand it now thanks again

11. mathslover Group Title

You're welcome. $$\textbf{Welcome to OpenStudy}$$

12. joylee Group Title

I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here

13. mathslover Group Title

Great to know, best of luck!

14. joylee Group Title

thanks