## joylee one year ago I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C

1. mathslover

@joylee first of all do you know what A' is?

2. joylee

not really

3. mathslover

A' = U - A

4. mathslover

|dw:1364714656096:dw|

5. naatiq

A' will be U-A = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)

6. mathslover

The shaded area above is A'

7. mathslover

@naatiq is right. A' = 0 $$A' \cap C$$ = $$0 \cap \{2,4,6,8,...\}$$ |dw:1364714988770:dw| In the figure, we have two sets : first containing zero and other one containing $$\{2,4,6,8..\}$$

8. mathslover

So it is clear that $$A'\cap C = \{0\} \cap \{2,4,6,8,...\}$$ = $$\phi$$ (empty set)

9. mathslover

Got it @joylee ?

10. joylee

yes and thanks guys for your help I think I understand it now thanks again

11. mathslover

You're welcome. $$\textbf{Welcome to OpenStudy}$$

12. joylee

I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here

13. mathslover

Great to know, best of luck!

14. joylee

thanks