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joylee

  • 3 years ago

I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C

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  1. mathslover
    • 3 years ago
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    @joylee first of all do you know what A' is?

  2. joylee
    • 3 years ago
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    not really

  3. mathslover
    • 3 years ago
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    A' = U - A

  4. mathslover
    • 3 years ago
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    |dw:1364714656096:dw|

  5. naatiq
    • 3 years ago
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    A' will be U-A = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)

  6. mathslover
    • 3 years ago
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    The shaded area above is A'

  7. mathslover
    • 3 years ago
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    @naatiq is right. A' = 0 \(A' \cap C\) = \(0 \cap \{2,4,6,8,...\}\) |dw:1364714988770:dw| In the figure, we have two sets : first containing zero and other one containing \(\{2,4,6,8..\}\)

  8. mathslover
    • 3 years ago
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    So it is clear that \(A'\cap C = \{0\} \cap \{2,4,6,8,...\}\) = \(\phi\) (empty set)

  9. mathslover
    • 3 years ago
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    Got it @joylee ?

  10. joylee
    • 3 years ago
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    yes and thanks guys for your help I think I understand it now thanks again

  11. mathslover
    • 3 years ago
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    You're welcome. \(\textbf{Welcome to OpenStudy}\)

  12. joylee
    • 3 years ago
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    I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here

  13. mathslover
    • 3 years ago
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    Great to know, best of luck!

  14. joylee
    • 3 years ago
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    thanks

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