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joylee
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I'm asking again just so I understand this question.
U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C
 one year ago
 one year ago
joylee Group Title
I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C
 one year ago
 one year ago

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mathslover Group TitleBest ResponseYou've already chosen the best response.1
@joylee first of all do you know what A' is?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
A' = U  A
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
dw:1364714656096:dw
 one year ago

naatiq Group TitleBest ResponseYou've already chosen the best response.1
A' will be UA = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
The shaded area above is A'
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
@naatiq is right. A' = 0 \(A' \cap C\) = \(0 \cap \{2,4,6,8,...\}\) dw:1364714988770:dw In the figure, we have two sets : first containing zero and other one containing \(\{2,4,6,8..\}\)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
So it is clear that \(A'\cap C = \{0\} \cap \{2,4,6,8,...\}\) = \(\phi\) (empty set)
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
Got it @joylee ?
 one year ago

joylee Group TitleBest ResponseYou've already chosen the best response.0
yes and thanks guys for your help I think I understand it now thanks again
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
You're welcome. \(\textbf{Welcome to OpenStudy}\)
 one year ago

joylee Group TitleBest ResponseYou've already chosen the best response.0
I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
Great to know, best of luck!
 one year ago
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