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joylee

I'm asking again just so I understand this question. U=(0,1,2,3,4,5....) A=(1,2,3,4...) B=(4,8,12,16...) and C=(2,4,6,8...) Determine the following A' intersection C

  • one year ago
  • one year ago

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  1. mathslover
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    @joylee first of all do you know what A' is?

    • one year ago
  2. joylee
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    not really

    • one year ago
  3. mathslover
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    A' = U - A

    • one year ago
  4. mathslover
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    |dw:1364714656096:dw|

    • one year ago
  5. naatiq
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    A' will be U-A = (0) , { basically U is enitre set of whole numbers and A is entire set of natural numbers} A' intersection C will be null set since C doesnot have (0)

    • one year ago
  6. mathslover
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    The shaded area above is A'

    • one year ago
  7. mathslover
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    @naatiq is right. A' = 0 \(A' \cap C\) = \(0 \cap \{2,4,6,8,...\}\) |dw:1364714988770:dw| In the figure, we have two sets : first containing zero and other one containing \(\{2,4,6,8..\}\)

    • one year ago
  8. mathslover
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    So it is clear that \(A'\cap C = \{0\} \cap \{2,4,6,8,...\}\) = \(\phi\) (empty set)

    • one year ago
  9. mathslover
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    Got it @joylee ?

    • one year ago
  10. joylee
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    yes and thanks guys for your help I think I understand it now thanks again

    • one year ago
  11. mathslover
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    You're welcome. \(\textbf{Welcome to OpenStudy}\)

    • one year ago
  12. joylee
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    I'm glad I joined in here and you guys has helped me and I'm glad to meet everyone in here

    • one year ago
  13. mathslover
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    Great to know, best of luck!

    • one year ago
  14. joylee
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    thanks

    • one year ago
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