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a+b/2

Sqrt[(Sum(Xi-(a+b/2)/2)]

I Couldn't get a word.

Step by Step would be easier.

Ask a concrete question, please.

Okay i got the first two equations but the last one i couldn't get.

Are we subtracting 100 items out of it?

Got it (y).

What next?

I know i am just terrible. :/

I'll do this one later.

Thanks anyways.

@klimenkov I have another question Can i post that now?

Sure.

Gimme a sec

This one.

Variance and standard deviation are the same?

No
SD=Sqrt(Variance)

Tell me honestly: do you need just answers?

No

Now please explain

\[Mean=\frac{ \sum_{i=1}^{n} X_i}{ n }\]

\[Variance=\frac{ \sum_{i=1}^{n}(X_i-X(mean) )^2}{n}\]

@klimenkov Right?

Yes. That is right.

-18 right?

76 for the b part?

6 for part c?

Yes.

For part d its 2-(5n/6)

Write the answer for d), please.

The answer for d is 2-5n/6

No No wait.

The answer to d is 1.167

@klimenkov Right?

Yes.

Now Variance?

Did i draw the equations correctly?

Yes.

So here we know mean of x and y so should we replace it by 12 and 16 in the equations?

You have to find the sum\[\sum_{i=1}^n (2x_i-3y_i+6-(-18))^2\]using variances that you have.

Where did 18 coming from now?

This is the mean of \(2x_i-3y_i+6\).

How do we get that?

You count this by yourself. Look higher:
-18 right?

I am not getting it :/

How are you calculating the mean here was my question

Because we have mean x as 12 and mean y as 16