waheguru 2 years ago This is a quadratics question and can someone help me graph this

1. waheguru

2. abb0t

If there's $$x^2$$ it's a parabola.

3. waheguru

I know but How Do I graph It

4. waheguru

How do I make a proper table of values?

5. waheguru

Do I just guess or is there a way of finding good numbers for x

6. abb0t

You could make a table and pick some points. Say, -2,-1,0,1,2 ?

7. waheguru

Ill try that again but last time i did it i was not getting a curve

8. waheguru

The values I did were -20 -10 0 10 20

9. waheguru

For example For -10 i am getting -9 for y and for 10 i am getting 7.6 for y. This means the graph is not symmetrical

10. UnkleRhaukus

that just means its not symmetrical about the y axis choose x=0,20,40,60,80,100,120 you'll find it symmetrical about x=60

11. satellite73

you are looking at the graph

12. waheguru

I have another question. SO this was not symmetrical along the y axis and when I was making my table of values, I was not able to get a cororect parabola. How can I fnid out wether I should make the x values all positive or negative so I do get the symmetrical point in my table of values?

13. goformit100

|dw:1364746001591:dw|

14. waheguru

Oh, We jsut learned quadratic relations and we have not come accross this formula i guess we will learn this soon

15. waheguru

Thanks for he help

16. satellite73

it says "use graphing technology" so you are allowed to cheat http://www.wolframalpha.com/input/?i=-x^2%2F144%2B5%2F6x++domain+0..120

17. UnkleRhaukus

you can find the x coordinate of the vertex of the parabola by x=-b/2a

18. satellite73

i meant multiply by 144

19. satellite73

$-\frac{1}{144}x^2+\frac{5}{6}x=0$ multiply by -144 to get $x^2-120x=0$ factor as $x(x-120)=0$

20. satellite73

gives the two zero highest point is smack dab in the middle

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