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waheguru
 one year ago
This is a quadratics question and can someone help me graph this
waheguru
 one year ago
This is a quadratics question and can someone help me graph this

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abb0t
 one year ago
Best ResponseYou've already chosen the best response.0If there's \(x^2\) it's a parabola.

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0I know but How Do I graph It

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0How do I make a proper table of values?

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0Do I just guess or is there a way of finding good numbers for x

abb0t
 one year ago
Best ResponseYou've already chosen the best response.0You could make a table and pick some points. Say, 2,1,0,1,2 ?

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0Ill try that again but last time i did it i was not getting a curve

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0The values I did were 20 10 0 10 20

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0For example For 10 i am getting 9 for y and for 10 i am getting 7.6 for y. This means the graph is not symmetrical

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1that just means its not symmetrical about the y axis choose x=0,20,40,60,80,100,120 you'll find it symmetrical about x=60

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1you are looking at the graph

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0I have another question. SO this was not symmetrical along the y axis and when I was making my table of values, I was not able to get a cororect parabola. How can I fnid out wether I should make the x values all positive or negative so I do get the symmetrical point in my table of values?

goformit100
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364746001591:dw

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0Oh, We jsut learned quadratic relations and we have not come accross this formula i guess we will learn this soon

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1it says "use graphing technology" so you are allowed to cheat http://www.wolframalpha.com/input/?i=x^2%2F144%2B5%2F6x++domain+0..120

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.1you can find the x coordinate of the vertex of the parabola by x=b/2a

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1i meant multiply by 144

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{144}x^2+\frac{5}{6}x=0\] multiply by 144 to get \[x^2120x=0\] factor as \[x(x120)=0\]

satellite73
 one year ago
Best ResponseYou've already chosen the best response.1gives the two zero highest point is smack dab in the middle
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