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waheguru Group Title

This is a quadratics question and can someone help me graph this

  • one year ago
  • one year ago

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  1. waheguru Group Title
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    • one year ago
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  2. abb0t Group Title
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    If there's \(x^2\) it's a parabola.

    • one year ago
  3. waheguru Group Title
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    I know but How Do I graph It

    • one year ago
  4. waheguru Group Title
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    How do I make a proper table of values?

    • one year ago
  5. waheguru Group Title
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    Do I just guess or is there a way of finding good numbers for x

    • one year ago
  6. abb0t Group Title
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    You could make a table and pick some points. Say, -2,-1,0,1,2 ?

    • one year ago
  7. waheguru Group Title
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    Ill try that again but last time i did it i was not getting a curve

    • one year ago
  8. waheguru Group Title
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    The values I did were -20 -10 0 10 20

    • one year ago
  9. waheguru Group Title
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    For example For -10 i am getting -9 for y and for 10 i am getting 7.6 for y. This means the graph is not symmetrical

    • one year ago
  10. UnkleRhaukus Group Title
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    that just means its not symmetrical about the y axis choose x=0,20,40,60,80,100,120 you'll find it symmetrical about x=60

    • one year ago
  11. satellite73 Group Title
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    you are looking at the graph

    • one year ago
  12. waheguru Group Title
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    I have another question. SO this was not symmetrical along the y axis and when I was making my table of values, I was not able to get a cororect parabola. How can I fnid out wether I should make the x values all positive or negative so I do get the symmetrical point in my table of values?

    • one year ago
  13. goformit100 Group Title
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    |dw:1364746001591:dw|

    • one year ago
  14. waheguru Group Title
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    Oh, We jsut learned quadratic relations and we have not come accross this formula i guess we will learn this soon

    • one year ago
  15. waheguru Group Title
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    Thanks for he help

    • one year ago
  16. satellite73 Group Title
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    it says "use graphing technology" so you are allowed to cheat http://www.wolframalpha.com/input/?i=-x^2%2F144%2B5%2F6x++domain+0..120

    • one year ago
  17. UnkleRhaukus Group Title
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    you can find the x coordinate of the vertex of the parabola by x=-b/2a

    • one year ago
  18. satellite73 Group Title
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    i meant multiply by 144

    • one year ago
  19. satellite73 Group Title
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    \[-\frac{1}{144}x^2+\frac{5}{6}x=0\] multiply by -144 to get \[x^2-120x=0\] factor as \[x(x-120)=0\]

    • one year ago
  20. satellite73 Group Title
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    gives the two zero highest point is smack dab in the middle

    • one year ago
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