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waheguru
 3 years ago
This is a quadratics question and can someone help me graph this
waheguru
 3 years ago
This is a quadratics question and can someone help me graph this

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abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0If there's \(x^2\) it's a parabola.

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0I know but How Do I graph It

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0How do I make a proper table of values?

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0Do I just guess or is there a way of finding good numbers for x

abb0t
 3 years ago
Best ResponseYou've already chosen the best response.0You could make a table and pick some points. Say, 2,1,0,1,2 ?

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0Ill try that again but last time i did it i was not getting a curve

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0The values I did were 20 10 0 10 20

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0For example For 10 i am getting 9 for y and for 10 i am getting 7.6 for y. This means the graph is not symmetrical

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1that just means its not symmetrical about the y axis choose x=0,20,40,60,80,100,120 you'll find it symmetrical about x=60

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are looking at the graph

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0I have another question. SO this was not symmetrical along the y axis and when I was making my table of values, I was not able to get a cororect parabola. How can I fnid out wether I should make the x values all positive or negative so I do get the symmetrical point in my table of values?

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364746001591:dw

waheguru
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, We jsut learned quadratic relations and we have not come accross this formula i guess we will learn this soon

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it says "use graphing technology" so you are allowed to cheat http://www.wolframalpha.com/input/?i=x^2%2F144%2B5%2F6x++domain+0..120

UnkleRhaukus
 3 years ago
Best ResponseYou've already chosen the best response.1you can find the x coordinate of the vertex of the parabola by x=b/2a

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i meant multiply by 144

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{144}x^2+\frac{5}{6}x=0\] multiply by 144 to get \[x^2120x=0\] factor as \[x(x120)=0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0gives the two zero highest point is smack dab in the middle
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