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If there's \(x^2\) it's a parabola.

I know but How Do I graph It

How do I make a proper table of values?

Do I just guess or is there a way of finding good numbers for x

You could make a table and pick some points. Say, -2,-1,0,1,2 ?

Ill try that again but last time i did it i was not getting a curve

The values I did were
-20
-10
0
10
20

you are looking at the graph

|dw:1364746001591:dw|

Thanks for he help

you can find the x coordinate of the vertex of the parabola by x=-b/2a

i meant multiply by 144

\[-\frac{1}{144}x^2+\frac{5}{6}x=0\] multiply by -144 to get
\[x^2-120x=0\] factor as
\[x(x-120)=0\]

gives the two zero
highest point is smack dab in the middle