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Find the force on any vertice on a cube because of the rest.All edges have same charge i.e q.
 one year ago
 one year ago
Find the force on any vertice on a cube because of the rest.All edges have same charge i.e q.
 one year ago
 one year ago

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goformit100Best ResponseYou've already chosen the best response.0
Use coulombs law to find the Required Answer...
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
dw:1364749278793:dw
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
and ON the surface of cube?
 one year ago

DLSBest ResponseYou've already chosen the best response.1
please leave it till here,i want to try it.
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
knock your self out :)
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
but, your question says, "find the charge"?
 one year ago

DLSBest ResponseYou've already chosen the best response.1
that place u assumed as 0,0,0 we have to find there due to rest 7 charges
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
no. force at any point on the cube. so, a point P on the cube.
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
well, off you go then.
 one year ago

MashyBest ResponseYou've already chosen the best response.1
and i didn't get the question.. is it to find the electric field at any point on the cube?!
 one year ago

MashyBest ResponseYou've already chosen the best response.1
there is a difference between vertices and edge you know :P.. all charges are on the VERTICES.. so you need to find electric field at any point on an edge?!
 one year ago

MashyBest ResponseYou've already chosen the best response.1
its 3d vector analysis man :/
 one year ago

MashyBest ResponseYou've already chosen the best response.1
its not easy.. you ll have to go brutal math here!
 one year ago

MashyBest ResponseYou've already chosen the best response.1
yea then its piece of cake.. just use i j k form.. !
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
@shubhamsrg Who else? :')
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
E at any point on the edge ? this can't be the question, please recheck.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
dw:1364751725488:dw Please circle/mark the position where you want to find the electric field
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
a charge is kept there? and we have to find E on that? _
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.0
hmm, so you want to find the net force acting on the charge.
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
force nikalni hai? lol
 one year ago

yrelhan4Best ResponseYou've already chosen the best response.0
Hmm shayad ho jayega. but abhi nhi kr rha mai. biomolecules kr rha hun.
 one year ago

MashyBest ResponseYou've already chosen the best response.1
Dls.. you seriously need to get your terminologies right :/.. !!!!
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
It does not matter at what corner you find the net force. use the 3D distance vectors. The individual forces would be way easier that way.
 one year ago

MashyBest ResponseYou've already chosen the best response.1
yea... just use position vectors as marked.. and keep your Forces in i j k format.. and then finally add them up and get the magnitude !!
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
dw:1364753502863:dw and so on
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
they'd all have a common factor of \[k{q^2\over a^2}\]
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
just be careful with the signs.. since the forces will be directed along the position vectors but in opposite direction
 one year ago

DLSBest ResponseYou've already chosen the best response.1
dw:1364821535025:dw Naming them like that for meanwhile. Now what I have is, \[\large F_{DA}=\frac{kq^2}{a^2}\] \[\large F_{CA}=\frac{kq^2}{\sqrt{2a}^2}cos45^0\] Fca=Fba am i correct with the magnitudes till here?help me determining the directions too! i want to clarify everything tilll this point first.
 one year ago

DLSBest ResponseYou've already chosen the best response.1
in the end i meant Fba=Fda* sorry
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
if you mean \[F_{CA}=\frac{kq^2}{a\sqrt{2}}\] then you are correct. since all charges are alike, the forces are repulsive and act along the distance vectors from other charge to A.\\ in my above diagram I give two such directions. look it up
 one year ago

DLSBest ResponseYou've already chosen the best response.1
yes i meant a root 2 only sorry!
 one year ago

DLSBest ResponseYou've already chosen the best response.1
I didn't get the direction part,where will the force act?
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
that cos 45 should not be there!
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
how did you get it to begin with?
 one year ago

DLSBest ResponseYou've already chosen the best response.1
IDK when we take components and when not :/ im so confused..
 one year ago

DLSBest ResponseYou've already chosen the best response.1
my teacher taught me though,im still messed up with everything.
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
"components of a force" you are talking about magnitude. do not include that cos... it'd show up automatically with the vectors.
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
when you take vectors like they are, all the things come with it like a package.
 one year ago

DLSBest ResponseYou've already chosen the best response.1
okay so dealing with only mag,im correct till here?
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
yes. but if you take cos 45, you'd have to take unit vectors.. this increases your work. my advice, do not take that cos45 and simply find the vectors
 one year ago

DLSBest ResponseYou've already chosen the best response.1
yes i eliminated that ,rest is correct right? and just that a root 2 thing
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
yes. rest seems fine.
 one year ago

electrokidBest ResponseYou've already chosen the best response.1
take hintf from the previous picture
 one year ago