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DLS
 one year ago
Find the force on any vertice on a cube because of the rest.All edges have same charge i.e q.
DLS
 one year ago
Find the force on any vertice on a cube because of the rest.All edges have same charge i.e q.

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goformit100
 one year ago
Best ResponseYou've already chosen the best response.0Use coulombs law to find the Required Answer...

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364749278793:dw

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1and ON the surface of cube?

DLS
 one year ago
Best ResponseYou've already chosen the best response.1please leave it till here,i want to try it.

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1knock your self out :)

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1but, your question says, "find the charge"?

DLS
 one year ago
Best ResponseYou've already chosen the best response.1that place u assumed as 0,0,0 we have to find there due to rest 7 charges

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1no. force at any point on the cube. so, a point P on the cube.

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1well, off you go then.

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1and i didn't get the question.. is it to find the electric field at any point on the cube?!

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1there is a difference between vertices and edge you know :P.. all charges are on the VERTICES.. so you need to find electric field at any point on an edge?!

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1its 3d vector analysis man :/

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1its not easy.. you ll have to go brutal math here!

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1yea then its piece of cake.. just use i j k form.. !

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0@shubhamsrg Who else? :')

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0E at any point on the edge ? this can't be the question, please recheck.

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364751725488:dw Please circle/mark the position where you want to find the electric field

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0a charge is kept there? and we have to find E on that? _

shubhamsrg
 one year ago
Best ResponseYou've already chosen the best response.0hmm, so you want to find the net force acting on the charge.

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0force nikalni hai? lol

yrelhan4
 one year ago
Best ResponseYou've already chosen the best response.0Hmm shayad ho jayega. but abhi nhi kr rha mai. biomolecules kr rha hun.

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1Dls.. you seriously need to get your terminologies right :/.. !!!!

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1It does not matter at what corner you find the net force. use the 3D distance vectors. The individual forces would be way easier that way.

Mashy
 one year ago
Best ResponseYou've already chosen the best response.1yea... just use position vectors as marked.. and keep your Forces in i j k format.. and then finally add them up and get the magnitude !!

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364753502863:dw and so on

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1they'd all have a common factor of \[k{q^2\over a^2}\]

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1just be careful with the signs.. since the forces will be directed along the position vectors but in opposite direction

DLS
 one year ago
Best ResponseYou've already chosen the best response.1dw:1364821535025:dw Naming them like that for meanwhile. Now what I have is, \[\large F_{DA}=\frac{kq^2}{a^2}\] \[\large F_{CA}=\frac{kq^2}{\sqrt{2a}^2}cos45^0\] Fca=Fba am i correct with the magnitudes till here?help me determining the directions too! i want to clarify everything tilll this point first.

DLS
 one year ago
Best ResponseYou've already chosen the best response.1in the end i meant Fba=Fda* sorry

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1if you mean \[F_{CA}=\frac{kq^2}{a\sqrt{2}}\] then you are correct. since all charges are alike, the forces are repulsive and act along the distance vectors from other charge to A.\\ in my above diagram I give two such directions. look it up

DLS
 one year ago
Best ResponseYou've already chosen the best response.1yes i meant a root 2 only sorry!

DLS
 one year ago
Best ResponseYou've already chosen the best response.1I didn't get the direction part,where will the force act?

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1that cos 45 should not be there!

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1how did you get it to begin with?

DLS
 one year ago
Best ResponseYou've already chosen the best response.1IDK when we take components and when not :/ im so confused..

DLS
 one year ago
Best ResponseYou've already chosen the best response.1my teacher taught me though,im still messed up with everything.

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1"components of a force" you are talking about magnitude. do not include that cos... it'd show up automatically with the vectors.

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1when you take vectors like they are, all the things come with it like a package.

DLS
 one year ago
Best ResponseYou've already chosen the best response.1okay so dealing with only mag,im correct till here?

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1yes. but if you take cos 45, you'd have to take unit vectors.. this increases your work. my advice, do not take that cos45 and simply find the vectors

DLS
 one year ago
Best ResponseYou've already chosen the best response.1yes i eliminated that ,rest is correct right? and just that a root 2 thing

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1yes. rest seems fine.

electrokid
 one year ago
Best ResponseYou've already chosen the best response.1take hintf from the previous picture

DLS
 one year ago
Best ResponseYou've already chosen the best response.1please tell me how to do that XZ thing :