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anonymous
 3 years ago
for resonance in closed column freq. = (2p+1)*vel/4l . but in class 10 i learned for resonance with a tuning fork say 512 hz this value of frequency should be 512 hz only . so my question if i put p =1,2,3... how to prove that the frequency is remaining same .
anonymous
 3 years ago
for resonance in closed column freq. = (2p+1)*vel/4l . but in class 10 i learned for resonance with a tuning fork say 512 hz this value of frequency should be 512 hz only . so my question if i put p =1,2,3... how to prove that the frequency is remaining same .

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0some one please comment what ever you feel about my question

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i know the length is changing but how to mathematically get it proved that the freq. is remaining constant

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0come on frnds anybody reply
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