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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

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at max height v= 0 so v^2 = u^2 - 2gs . v= 0 . so s = u^2/2g 20*20/2*10
does it include a formula?
yes its a formula where g = gravitational acceleration

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Other answers:

40/20 is 2 is that the answer?
no 200 is the answer check the calculation
`the answers i have that are close to 200 are 20.4 or 2.04
can you help me?
at highest point v=0 we know v=u - gt g=9.8 u=20 v=0 t=u/g=20/9.8=2.04
u can also get by using formula s=u*t-.5*g*t^2 s=24 u=20 g=9.8 solve for t

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