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destineeeee

  • 2 years ago

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

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  1. mailtoarko
    • 2 years ago
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    at max height v= 0 so v^2 = u^2 - 2gs . v= 0 . so s = u^2/2g 20*20/2*10

  2. destineeeee
    • 2 years ago
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    does it include a formula?

  3. mailtoarko
    • 2 years ago
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    yes its a formula where g = gravitational acceleration

  4. destineeeee
    • 2 years ago
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    40/20 is 2 is that the answer?

  5. mailtoarko
    • 2 years ago
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    yes

  6. mailtoarko
    • 2 years ago
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    no 200 is the answer check the calculation

  7. destineeeee
    • 2 years ago
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    `the answers i have that are close to 200 are 20.4 or 2.04

  8. destineeeee
    • 2 years ago
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    can you help me?

  9. swarup169
    • 2 years ago
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    at highest point v=0 we know v=u - gt g=9.8 u=20 v=0 t=u/g=20/9.8=2.04

  10. swarup169
    • 2 years ago
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    u can also get by using formula s=u*t-.5*g*t^2 s=24 u=20 g=9.8 solve for t

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