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An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.
 one year ago
 one year ago
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.
 one year ago
 one year ago

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mailtoarkoBest ResponseYou've already chosen the best response.1
at max height v= 0 so v^2 = u^2  2gs . v= 0 . so s = u^2/2g 20*20/2*10
 one year ago

destineeeeeBest ResponseYou've already chosen the best response.0
does it include a formula?
 one year ago

mailtoarkoBest ResponseYou've already chosen the best response.1
yes its a formula where g = gravitational acceleration
 one year ago

destineeeeeBest ResponseYou've already chosen the best response.0
40/20 is 2 is that the answer?
 one year ago

mailtoarkoBest ResponseYou've already chosen the best response.1
no 200 is the answer check the calculation
 one year ago

destineeeeeBest ResponseYou've already chosen the best response.0
`the answers i have that are close to 200 are 20.4 or 2.04
 one year ago

swarup169Best ResponseYou've already chosen the best response.0
at highest point v=0 we know v=u  gt g=9.8 u=20 v=0 t=u/g=20/9.8=2.04
 one year ago

swarup169Best ResponseYou've already chosen the best response.0
u can also get by using formula s=u*t.5*g*t^2 s=24 u=20 g=9.8 solve for t
 one year ago
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