anonymous
  • anonymous
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.
Physics
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anonymous
  • anonymous
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.
Physics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
at max height v= 0 so v^2 = u^2 - 2gs . v= 0 . so s = u^2/2g 20*20/2*10
anonymous
  • anonymous
does it include a formula?
anonymous
  • anonymous
yes its a formula where g = gravitational acceleration

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anonymous
  • anonymous
40/20 is 2 is that the answer?
anonymous
  • anonymous
yes
anonymous
  • anonymous
no 200 is the answer check the calculation
anonymous
  • anonymous
`the answers i have that are close to 200 are 20.4 or 2.04
anonymous
  • anonymous
can you help me?
anonymous
  • anonymous
at highest point v=0 we know v=u - gt g=9.8 u=20 v=0 t=u/g=20/9.8=2.04
anonymous
  • anonymous
u can also get by using formula s=u*t-.5*g*t^2 s=24 u=20 g=9.8 solve for t

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