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anonymous
 3 years ago
find general solution of this differential equation
dy/dx = y2
anonymous
 3 years ago
find general solution of this differential equation dy/dx = y2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, its easily variable separable, dy/ (y2) =dx did you try integrating this ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no...i got confused if i need to subtract it or what

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no subtract. dy/ (y2) =dx got this ? can you integrate ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh ya...is the answer dw:1364766331963:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes, now do you need to isolate 'y' also ? if not, thats your answer.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya i need to get y out

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then use log properties.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lets say we getta find c at x=1, y=1 how?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you are making this up ? general solution means we need 'c' nevertheless, y can't be 1 here.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364766554143:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya i am making up...now lets find particular solution

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0y must be >=2 so that log term is defined...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ln of negative numbers are not defined in reals.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then we can't find c?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do we need to find 'c'? and yes, if x=y=1, then c is complex number...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes we need to find particular solution

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.1integrating gives ln (y  2) = x + c so y  2 = e^(x + c) = e^x * e*c = Ae^x y = Ae^x + 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh, good....now we don't have to actually worry about c being complex..

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no we dont its calculus

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you didn't get this ? : ln (y  2) = x + c so y  2 = e^(x + c) = e^x * e*c = Ae^x y = Ae^x + 2 what you have doubt with ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0just plug in x=1, y=1 there,and you'll get A

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok now the initial condition is y(0)=1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so, put x=0 y=1 this should not be any problem...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364767623910:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1364767697343:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no, put e^c = A you can keep the general form in A and A=2 is valid.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to find a constant, not specifically 'c' A can be used, as valid constant.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can 1 put c1 and c2 instead....i really dont know what is A

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sure, you can even put 'Best_Mathematician' instead Best_Mathematician = 2 :P

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya whatever lol...so A is just a constant right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0haha thanks...do you want going further in this equation

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is your question...do you wanna go ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ya lol..... Use a technological tool and Euler's method with ten steps of size 0.1 to estimate y(1). Make certain to include supporting screen captures.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0sorry... that was latin to me :P
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