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iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1oh, its easily variable separable, dy/ (y2) =dx did you try integrating this ?

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0no...i got confused if i need to subtract it or what

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1no subtract. dy/ (y2) =dx got this ? can you integrate ?

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0oh ya...is the answer dw:1364766331963:dw

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1yes, now do you need to isolate 'y' also ? if not, thats your answer.

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0ya i need to get y out

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0as i need to find c

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1then use log properties.

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0lets say we getta find c at x=1, y=1 how?

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1you are making this up ? general solution means we need 'c' nevertheless, y can't be 1 here.

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364766554143:dw

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0ya i am making up...now lets find particular solution

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1y must be >=2 so that log term is defined...

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0no it is not

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0it is 1 and 1

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1ln of negative numbers are not defined in reals.

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0then we can't find c?

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1do we need to find 'c'? and yes, if x=y=1, then c is complex number...

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0yes we need to find particular solution

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0at y(1) = 1

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.1integrating gives ln (y  2) = x + c so y  2 = e^(x + c) = e^x * e*c = Ae^x y = Ae^x + 2

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1oh, good....now we don't have to actually worry about c being complex..

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0no we dont its calculus

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1you didn't get this ? : ln (y  2) = x + c so y  2 = e^(x + c) = e^x * e*c = Ae^x y = Ae^x + 2 what you have doubt with ?

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1just plug in x=1, y=1 there,and you'll get A

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0ok now the initial condition is y(0)=1

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1so, put x=0 y=1 this should not be any problem...

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364767623910:dw

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0dw:1364767697343:dw

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1no, put e^c = A you can keep the general form in A and A=2 is valid.

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1you have to find a constant, not specifically 'c' A can be used, as valid constant.

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0can 1 put c1 and c2 instead....i really dont know what is A

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1sure, you can even put 'Best_Mathematician' instead Best_Mathematician = 2 :P

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0ya whatever lol...so A is just a constant right

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0haha thanks...do you want going further in this equation

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1this is your question...do you wanna go ?

Best_Mathematician
 one year ago
Best ResponseYou've already chosen the best response.0ya lol..... Use a technological tool and Euler's method with ten steps of size 0.1 to estimate y(1). Make certain to include supporting screen captures.

iambehindyou
 one year ago
Best ResponseYou've already chosen the best response.1sorry... that was latin to me :P
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