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qrious126

  • 3 years ago

Hello, What is the general solution of the following differential equation? (1 + (x^3/y)sin^2x)dx + (1/y)(x + (1/cos^2(2y))dy = 0; I used the integrating factor, but I'm stuck at the following step: u(x) [-x^3sin^2x + 1] = u'(x) [x + (1/cos^2(2y)] Thanks in advance!

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  1. qrious126
    • 3 years ago
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    The original eq is: \[(1 + (x ^{3}/y)\sin ^{2} x)dx + (1/y)(x + (1/\cos ^{2}(2y))dy = 0\] I'm stuck at this step: \[u(x) [-xsin ^{2} x + 1] = u'(x) [x + (1/\cos ^{2}(2y)]\]

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