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gooday

  • one year ago

Very urgent! Please help me!! Red-green Color Blindness and Hemophilia A are both sex-linked traits in humans. Both genes are on the X-chromosome and are tightly linked. Individual 1 is homozygous normal woman married to individual 2 who is both red-green color blind and a hemophiliac.Individual 3 is their daughter who married to a normal man individual 4 and individual 5 is the as yet unborn son of them. What is the probability that their son, individual 5, will be both color blind and a hemophiliac?

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  1. thomaster
    • one year ago
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    So the mother is normal XX The father is color blind XiY (the i indicates that the gene is affected) To be color blind and hemophiliac a woman needs to have XiXi and a man needs XiY This is both the same for color blindness and hemophilia. A woman can also be XiX. This would mean she is a carrier of the affected gene but not affected by the disease. Their daughters will all be carriers because only the X chromosome of the man is affected. This drawing explains it: |dw:1364822066750:dw| Theire daughter with genotype XXi marries a man with genotype XY (the daughter is carrier for both color blindness and hemophilia) If they get children they'll end up according to the next drawing: |dw:1364822342412:dw| So the chance that their son will have both the diseases is 50%

  2. maaxx
    • one year ago
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    1 out of 4

  3. maaxx
    • one year ago
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    50%

  4. gooday
    • one year ago
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    Hi thomaster and maaxx, Thanks heaps for your great help!!! :)))

  5. Grad2013
    • one year ago
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    Thanks for your clear explanation F1 generation and F2 table was very useful!

  6. Grad2013
    • one year ago
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    thomaster! Thanks for the assistance and direction! Best regards!

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