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Red-green Color Blindness and Hemophilia A are both sex-linked traits in humans. Both genes are on the X-chromosome and are tightly linked.
Individual 1 is homozygous normal woman married to individual 2 who is both red-green color blind and a hemophiliac.Individual 3 is their daughter who married to a normal man individual 4 and individual 5 is the as yet unborn son of them.
What is the probability that their son, individual 5, will be both color blind and a hemophiliac?
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So the mother is normal XX
The father is color blind XiY (the i indicates that the gene is affected)
To be color blind and hemophiliac a woman needs to have XiXi and a man needs XiY
This is both the same for color blindness and hemophilia.
A woman can also be XiX. This would mean she is a carrier of the affected gene but not affected by the disease.
Their daughters will all be carriers because only the X chromosome of the man is affected.
This drawing explains it:
Theire daughter with genotype XXi marries a man with genotype XY
(the daughter is carrier for both color blindness and hemophilia)
If they get children they'll end up according to the next drawing:
So the chance that their son will have both the diseases is 50%