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waheguru

  • one year ago

I don't understand this question The sum of the first "n" natural numbers is a quadratic relation. Determine that relation and verify it for the first 6 natural numbers

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  1. Mertsj
    • one year ago
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    We would be talking about the sum of this arithmetic series: 1,2,3,4,5,...n-1, n

  2. waheguru
    • one year ago
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    Can you show me step by step how to solve this

  3. Mertsj
    • one year ago
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    I don't really know. I would hunt up the formula for the sum of an arithmetic series and see where that leads me.

  4. Mertsj
    • one year ago
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    http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalNumbers.htm

  5. electrokid
    • one year ago
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    natural number sequence is 1, 2, 3, 4, 5,/// notice that "0" is not a natural number

  6. electrokid
    • one year ago
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    this is an arithmatic sequence of difference "1" so, \[S_n={n\over2}[a_0+(n-1)d]\\ S_n={n\over2}[1+(n-1)]\\ S_n={n^2\over2}\]

  7. waheguru
    • one year ago
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    can you explain how you came up with the formula

  8. electrokid
    • one year ago
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    the formula \[S_n={n\over2}[a_0+(n-1)d]\] is the formula for the sum of "n" numbers in arithmetic series starting from "a0" with a common difference of "d"

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