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The sum of the first "n" natural numbers is a quadratic relation. Determine that relation and verify it for the first 6 natural numbers
 one year ago
 one year ago
I don't understand this question The sum of the first "n" natural numbers is a quadratic relation. Determine that relation and verify it for the first 6 natural numbers
 one year ago
 one year ago

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MertsjBest ResponseYou've already chosen the best response.0
We would be talking about the sum of this arithmetic series: 1,2,3,4,5,...n1, n
 one year ago

waheguruBest ResponseYou've already chosen the best response.0
Can you show me step by step how to solve this
 one year ago

MertsjBest ResponseYou've already chosen the best response.0
I don't really know. I would hunt up the formula for the sum of an arithmetic series and see where that leads me.
 one year ago

MertsjBest ResponseYou've already chosen the best response.0
http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalNumbers.htm
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
natural number sequence is 1, 2, 3, 4, 5,/// notice that "0" is not a natural number
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
this is an arithmatic sequence of difference "1" so, \[S_n={n\over2}[a_0+(n1)d]\\ S_n={n\over2}[1+(n1)]\\ S_n={n^2\over2}\]
 one year ago

waheguruBest ResponseYou've already chosen the best response.0
can you explain how you came up with the formula
 one year ago

electrokidBest ResponseYou've already chosen the best response.0
the formula \[S_n={n\over2}[a_0+(n1)d]\] is the formula for the sum of "n" numbers in arithmetic series starting from "a0" with a common difference of "d"
 one year ago
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