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 one year ago
I don't understand this question
The sum of the first "n" natural numbers is a quadratic relation. Determine that relation and verify it for the first 6 natural numbers
 one year ago
I don't understand this question The sum of the first "n" natural numbers is a quadratic relation. Determine that relation and verify it for the first 6 natural numbers

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0We would be talking about the sum of this arithmetic series: 1,2,3,4,5,...n1, n

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0Can you show me step by step how to solve this

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0I don't really know. I would hunt up the formula for the sum of an arithmetic series and see where that leads me.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0http://www.trans4mind.com/personal_development/mathematics/series/sumNaturalNumbers.htm

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0natural number sequence is 1, 2, 3, 4, 5,/// notice that "0" is not a natural number

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0this is an arithmatic sequence of difference "1" so, \[S_n={n\over2}[a_0+(n1)d]\\ S_n={n\over2}[1+(n1)]\\ S_n={n^2\over2}\]

waheguru
 one year ago
Best ResponseYou've already chosen the best response.0can you explain how you came up with the formula

electrokid
 one year ago
Best ResponseYou've already chosen the best response.0the formula \[S_n={n\over2}[a_0+(n1)d]\] is the formula for the sum of "n" numbers in arithmetic series starting from "a0" with a common difference of "d"
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