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xxdgffsdgdfgffgsg

Can someone help me graph this equation step by step 1.x^2-6x+8=0

  • one year ago
  • one year ago

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  1. qpHalcy0n
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    First, do you know what basic shape that function makes?

    • one year ago
  2. xxdgffsdgdfgffgsg
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    |dw:1364839464696:dw|

    • one year ago
  3. qpHalcy0n
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    Right. So the vertex is the lowest (or highest) point on the graph. You can find the x-coordinate of the vertex using -b/2a. Do you know what the a, b, and c terms are?

    • one year ago
  4. xxdgffsdgdfgffgsg
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    ok a =1 b=-6 c=8

    • one year ago
  5. qpHalcy0n
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    Right, so -b/2a is what?

    • one year ago
  6. xxdgffsdgdfgffgsg
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    the answer would be 3 after doing all the steps

    • one year ago
  7. qpHalcy0n
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    Well, it means that the vertex is at x=3. To find the corresponding "y" of the vertex, plug 3 in for "x" in the function there.

    • one year ago
  8. xxdgffsdgdfgffgsg
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    (3,-1)

    • one year ago
  9. qpHalcy0n
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    Okay, so there's your vertex. You know the graph opens up because the quadratic (squared) term is positive. To find where it crosses the x-axis solve the equation for y = 0. It factors nicely: (x +/- ?)(x +/- ?)

    • one year ago
  10. xxdgffsdgdfgffgsg
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    so if x is positive it goes up if x is negative it goes down

    • one year ago
  11. qpHalcy0n
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    No, if x SQUARED is positive it goes up, (x^2)

    • one year ago
  12. qpHalcy0n
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    So how does that function factor. Anything multiply to give 8, but add to give -6?

    • one year ago
  13. xxdgffsdgdfgffgsg
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    4 and 2 both are negative

    • one year ago
  14. qpHalcy0n
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    Right, so (x - 4)(x - 2). Set each equal to 0 and solve. The solutions will be the x-values where the parabola crosses the x-axis.

    • one year ago
  15. xxdgffsdgdfgffgsg
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    ok I understand now thanks for all your help

    • one year ago
  16. qpHalcy0n
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    Np, you get those and you have your graph.

    • one year ago
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