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theanonymous27
 one year ago
Find a parametrization
r(t) = h x(t), y(t), z(t)i
of the straight line passing through the origin
in 3space whose projection on the xyplane
is a line with slope 4, while its projection on
the yzplane is a line with slope −3, i.e.,
∆y/∆x= 4,∆z/∆y= −3.
theanonymous27
 one year ago
Find a parametrization r(t) = h x(t), y(t), z(t)i of the straight line passing through the origin in 3space whose projection on the xyplane is a line with slope 4, while its projection on the yzplane is a line with slope −3, i.e., ∆y/∆x= 4,∆z/∆y= −3.

This Question is Closed

wio
 one year ago
Best ResponseYou've already chosen the best response.1Can you come up with a vector which goes in the correct direction?

wio
 one year ago
Best ResponseYou've already chosen the best response.1First, it doesn't matter what the magnitude of the vector is... so we get to chose one of the components as long as the others are correctly proportional.

wio
 one year ago
Best ResponseYou've already chosen the best response.1Our vector only has to have the right direction.

wio
 one year ago
Best ResponseYou've already chosen the best response.1@theanonymous27 Does this make sense?

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0I understand, but how can I find that vector? what I dont get is how can I use the slopes here to find what I need

wio
 one year ago
Best ResponseYou've already chosen the best response.1So we can start by letting our \(x\) component be 1:\[ \mathbf{v} = \begin{bmatrix} x_1 \\ y_1 \\ z_1 \end{bmatrix} = \begin{bmatrix} 1 \\ y_1 \\ z_1 \end{bmatrix} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1Since \(\Delta y/\Delta x= 4\) and \(\Delta x = 1\), what must \(\Delta y\) be?

wio
 one year ago
Best ResponseYou've already chosen the best response.1We use the slopes to figure out the proportions between each component, @theanonymous27

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0so <Y is 4, and then we get that Z has to be 12

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0so does the slope represent the component of the vector?

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0we end up with r(t) = <t, 4, 12t> ? is that right?

wio
 one year ago
Best ResponseYou've already chosen the best response.1So given the direction vector \(\mathbf{v}\) and some point which the line goes though \(\mathbf{b}\) the parametrization for our line is: \[ \mathbf{r}(t) = \mathbf{v}t+\mathbf{b} \]

wio
 one year ago
Best ResponseYou've already chosen the best response.1\[ r(t) = \begin{bmatrix} 1 \\ 4 \\ 12 \end{bmatrix} t + \begin{bmatrix} 0 \\ 0 \\ 0 \end{bmatrix} = \begin{bmatrix} t \\ 4t \\ 12t \end{bmatrix} \]

theanonymous27
 one year ago
Best ResponseYou've already chosen the best response.0Thank you!, One last question... Why did you pick x=1 first? what would have happened if you choose y=1 instead

wio
 one year ago
Best ResponseYou've already chosen the best response.1If you pick \(y=1\) then you get \(x=1/4\) and \(z=3\)
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