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enay800

  • 3 years ago

dy/dx ln(xy)=xy^2-x

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  1. Azteck
    • 3 years ago
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    What are you meant to find or solve?

  2. Azteck
    • 3 years ago
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    \[\large \frac{dy}{dx} ln(xy)=xy^2-x\] \[\large \frac{dy}{dx}[lnx+lny]=xy^2-x\] \[\large \frac{1}{x}=xy^2-x\] \[\large 1=x^2y^2-x^2\] \[\large y^2=\frac{x^2+1}{x^2}\] \[\large y=\pm \frac{\sqrt{x^2+1}}{x}\]

  3. abdullatif92211
    • 3 years ago
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    this question can be solved using bernaoulli method

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