Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
DLS
Group Title
Simplify this!
\large \tan^{1} \frac{ \sqrt{1+x^2}1}{x},x \neq 0
 one year ago
 one year ago
DLS Group Title
Simplify this! \large \tan^{1} \frac{ \sqrt{1+x^2}1}{x},x \neq 0
 one year ago
 one year ago

This Question is Closed

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\large \tan^{1} \frac{ \sqrt{1+x^2}1}{x},x \neq 0\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
Master @ParthKohli
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Thanks for calling me, but I suck at trig :P
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
Hmm,nevermind tag someone better <3
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I have called the real master here.
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
I await to see him.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
He has seen my FB message. Let's see when he's here.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
He says he's coming.
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
I await I await!
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
Lets see who it is D:
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
Told you.
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
Got to go , I am giving you a hint : \[\tan ^{1 } (\cfrac{\sqrt{1+x^2}  1}{\sqrt{1+x^21}})\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE \tan^{1} \frac{\sec \theta1}{\tan \theta}=> \frac{1\cos \theta}{\sin \theta}\] used half angle formula and got it :
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
Will this property help you?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
@mathslover I just substituted x=tan theta
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
multiply both numerator and denominator by root(1+x^2) +1
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Then use the property given by @mathslover
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I don't fit in this genius world.
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
but substitution method is better :P
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
@ParthKohli may be because u r better than genius
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.1
:P if you love substitution or you think it is better or simpler then go for it but do try the another method also. It would be beneficial for you.
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.0
I am overrated _
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.